A companion to Euclid: being a help to the understanding and remembering of the first four books. With a set of improved figures, and an original demonstration of the proposition called in Euclid the twelfth axiom, by a graduateJohn W. Parker, 1837 - 88 sider |
Inni boken
Resultat 1-5 av 9
Side 26
... meet as in G , Prove , on that supposition , 1. that in the A EGF the exterior AEF = inter . and opp . EFD , which is impossible , and .. the supposition is false . 2. that similarly AB and CD do not meet towards A and c , 3 . E and ...
... meet as in G , Prove , on that supposition , 1. that in the A EGF the exterior AEF = inter . and opp . EFD , which is impossible , and .. the supposition is false . 2. that similarly AB and CD do not meet towards A and c , 3 . E and ...
Side 27
... meet if produced far enough , which shows the supposition to be false , and that LAGH = GHD . 4. Prove that LS EGB = GHD , 5 . 6 . that S EGB + BGHS BGH + GHD , that LS BGH + GHD 2 right Ls . * The proof of this proposition depends on ...
... meet if produced far enough , which shows the supposition to be false , and that LAGH = GHD . 4. Prove that LS EGB = GHD , 5 . 6 . that S EGB + BGHS BGH + GHD , that LS BGH + GHD 2 right Ls . * The proof of this proposition depends on ...
Side 28
... meet the two right lines AB , CD ; and let the S BKL , KLD be VE M K H B D together < 2 right Дs ; then shall AB , CB meet , if produced far enough , towards the points B and D. F Since lines which , when they are produced ever so far ...
... meet the two right lines AB , CD ; and let the S BKL , KLD be VE M K H B D together < 2 right Дs ; then shall AB , CB meet , if produced far enough , towards the points B and D. F Since lines which , when they are produced ever so far ...
Side 29
... meet . E Demon . Again , AB and CD will meet on that side of EF on which are thes which are < 2 rights ; For suppose them to meet on the other side of EF , as in M , then KML would be a A ; And since S AKL + BKL = 2 right Дs , and S CLK ...
... meet . E Demon . Again , AB and CD will meet on that side of EF on which are thes which are < 2 rights ; For suppose them to meet on the other side of EF , as in M , then KML would be a A ; And since S AKL + BKL = 2 right Дs , and S CLK ...
Side 35
... consequently HB and FE will meet ; and to state that FL is a of which LB , BF are complements of about the diameter HK . ים ms Steps of the Demonstration . 1. Prove that m LB c 2 FIRST BOOK . 35 Steps of the Demonstration. ...
... consequently HB and FE will meet ; and to state that FL is a of which LB , BF are complements of about the diameter HK . ים ms Steps of the Demonstration . 1. Prove that m LB c 2 FIRST BOOK . 35 Steps of the Demonstration. ...
Vanlige uttrykk og setninger
AB² AC² AD² AEX EC angle contained angle equal Argument ad absurdum base DF BC² BD² bisect CB² cuts the circle DC² Demonstration itself consists diameter EB² EF² EG² Engravings equal straight lines equi equiangular equilateral Euclid F Steps fall figure GF² given circle given point given rectilineal angle given straight line given triangle i. e. less inscribe interior angles learner less greater line be divided line drawn parallel parallelogram PARKER pass pentagon point of contact Problem proof PROPOSITION IX PROPOSITION VIII Proved by showing rectangle contained right angles right line shows the supposition similarly Suppose supposition is false Theorem WEST STRAND whole line
Populære avsnitt
Side 24 - If two triangles have two angles of the [one equal to two angles of the other, each to each, and one side equal to one side, namely, either t}le sides adjacent to the equal...
Side 45 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 18 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 61 - From this it is manifest that the straight line which is drawn at right angles to the diameter of a circle from the extremity of it, touches the circle...
Side 37 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 76 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Side 77 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it, and if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square on GEOMETRY.
Side 72 - If a straight line touch a circle, and from the point of contact a straight line be drawn at right angles to the touching line, the centre of the circle shall be in that line.
Side 27 - If a straight line fall on two parallel straight lines, it makes the alternate angles equal to one another, and the exterior angle equal to the interior and opposite angle on the same side; and also the two interior angles on the same side together equal to two right angles.