A companion to Euclid: being a help to the understanding and remembering of the first four books. With a set of improved figures, and an original demonstration of the proposition called in Euclid the twelfth axiom, by a graduate |
Inni boken
Resultat 1-5 av 5
Side 26
Euclides. ÆB straight lines makes the alternate angles equal to one 4 G another ,
these two straight lines shall be parallel . Steps of the Demonstration . Having
made the supposition that AB # cd , and s that they : . meet as in G , Prove , on
that ...
Euclides. ÆB straight lines makes the alternate angles equal to one 4 G another ,
these two straight lines shall be parallel . Steps of the Demonstration . Having
made the supposition that AB # cd , and s that they : . meet as in G , Prove , on
that ...
Side 28
If a right line meet two right lines , so as to make the two interior angles on the
same side of it taken together less than two right angles , these right lines being
continually produced , shall at length meet on that side on which are the angles ...
If a right line meet two right lines , so as to make the two interior angles on the
same side of it taken together less than two right angles , these right lines being
continually produced , shall at length meet on that side on which are the angles ...
Side 29
Z BAC = alternate / ACE , And since AB , CD are not parallels , they will meet .
Demon . Again , AB and cd will meet on that side of EF on which are the Zs which
are < 2 right Zs ; For suppose them to meet on the other side of EF , as in m , then
...
Z BAC = alternate / ACE , And since AB , CD are not parallels , they will meet .
Demon . Again , AB and cd will meet on that side of EF on which are the Zs which
are < 2 right Zs ; For suppose them to meet on the other side of EF , as in m , then
...
Side 80
( In the construction of the figure , prove that the perpendiculars DF and EF will
meet , as in F ) . ai 1 . Prove that ( in As ADF , BDF ) base BF = base AF , that
similarly cF = AF ; and : . AF , BF , CF = each other , 3 . that a o described with
centre F ...
( In the construction of the figure , prove that the perpendiculars DF and EF will
meet , as in F ) . ai 1 . Prove that ( in As ADF , BDF ) base BF = base AF , that
similarly cF = AF ; and : . AF , BF , CF = each other , 3 . that a o described with
centre F ...
Side 88
It should be observed that the triangle and pentagon must be so placed in the
circle , that one angle of each may meet in the same point A . THE END .
LONDON : - - John W . PARKER , ST . MARTIN ' S LANE . FOURTH BOOK .
It should be observed that the triangle and pentagon must be so placed in the
circle , that one angle of each may meet in the same point A . THE END .
LONDON : - - John W . PARKER , ST . MARTIN ' S LANE . FOURTH BOOK .
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Vanlige uttrykk og setninger
alternate angle contained angle equal applied Argument ad absurdum base bisect BOOK centre circumference coincides construction Demonstration described diameter directed divided draw drawn Edition Engravings equal equiangular equilateral Euclid extremities fall figure given circle given point given rectilineal given straight line greater HISTORY impossible inscribe interior joins learner least less meet Nature necessary opposite parallel parallelogram pass pentagon point of contact Problem produced proof PROPOSITION PROPOSITION VIII PROPOSITION XV Proved by showing READINGS rectangle contained right angles right line right Zs segment shows the supposition sides similarly square Steps straight line Suppose supposition is false Theorem touch triangle VOLUME whole whole line YOUNG
Populære avsnitt
Side 24 - If two triangles have two angles of the [one equal to two angles of the other, each to each, and one side equal to one side, namely, either t}le sides adjacent to the equal...
Side 45 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 18 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 61 - From this it is manifest that the straight line which is drawn at right angles to the diameter of a circle from the extremity of it, touches the circle...
Side 37 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 76 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Side 77 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it, and if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square on GEOMETRY.
Side 72 - If a straight line touch a circle, and from the point of contact a straight line be drawn at right angles to the touching line, the centre of the circle shall be in that line.
Side 27 - If a straight line fall on two parallel straight lines, it makes the alternate angles equal to one another, and the exterior angle equal to the interior and opposite angle on the same side; and also the two interior angles on the same side together equal to two right angles.
Bibliografisk informasjon
| Tittel | A companion to Euclid: being a help to the understanding and remembering of the first four books. With a set of improved figures, and an original demonstration of the proposition called in Euclid the twelfth axiom, by a graduate |
| Forfatter | Euclides |
| Utgiver | John W. Parker, 1837 |
| Original fra | Oxford University |
| Digitalisert | 16. okt 2006 |
| Lengde | 88 sider |
| Eksporter sitat | BiBTeX EndNote RefMan |