## A companion to Euclid: being a help to the understanding and remembering of the first four books. With a set of improved figures, and an original demonstration of the proposition called in Euclid the twelfth axiom, by a graduate |

### Inni boken

Resultat 1-5 av 5

Side 20

Any two angles of a triangle are together less than two right angles . Steps of the

Demonstration . 1 . Prove that Zs DCA + ACB > ZS ACB + CBA , that Zs ACB +

CBA < 2

Any two angles of a triangle are together less than two right angles . Steps of the

Demonstration . 1 . Prove that Zs DCA + ACB > ZS ACB + CBA , that Zs ACB +

CBA < 2

**right Zs**, 3 . that similarly each of the other pairs of Zs is < 2**right Zs**. 3 . Side 28

Proved by showing that the alternate

PROPOSITION . “ If a

angles on the same side of it taken together less than two

Proved by showing that the alternate

**ZS**AGK , GKD are equal . OOODCR DPROPOSITION . “ If a

**right**line meet two**right**lines , so as to make the two interiorangles on the same side of it taken together less than two

**right**angles , these**right**... Side 29

Again , AB and cd will meet on that side of EF on which are the Zs which are < 2

would be a A ; And since ZS AKL + BKL = 2

...

Again , AB and cd will meet on that side of EF on which are the Zs which are < 2

**right Zs**; For suppose them to meet on the other side of EF , as in m , then KMLwould be a A ; And since ZS AKL + BKL = 2

**right Zs**, 13 . 1 and Zs CLK + DLK = 2...

Side 30

... strange to a beginner , viz . , that the Zs at the vertex F , are said to be equal . . y

to 4

the Zs above the straight line MN are together equal to 2

... strange to a beginner , viz . , that the Zs at the vertex F , are said to be equal . . y

to 4

**right Zs**; but by in- - - - - - - specting the annexed figure he will perceive thatthe Zs above the straight line MN are together equal to 2

**right Zs**( by Prop . XIII . Side 72

That < in segment > 1 o is < right Ze is proved by showing that since Z BAC of A

ABC is a right 2 , . . the Z ARC < right Z . Steps of the Demonstration to Part 3rd ,

That _ in a segment < } o is > right L . 1 . Prove that ZS ABC + ADC = 2

...

That < in segment > 1 o is < right Ze is proved by showing that since Z BAC of A

ABC is a right 2 , . . the Z ARC < right Z . Steps of the Demonstration to Part 3rd ,

That _ in a segment < } o is > right L . 1 . Prove that ZS ABC + ADC = 2

**right Zs**. 2...

### Hva folk mener - Skriv en omtale

Vi har ikke funnet noen omtaler på noen av de vanlige stedene.

### Vanlige uttrykk og setninger

alternate angle contained angle equal applied Argument ad absurdum base bisect BOOK centre circumference coincides construction Demonstration described diameter directed divided draw drawn Edition Engravings equal equiangular equilateral Euclid extremities fall figure given circle given point given rectilineal given straight line greater HISTORY impossible inscribe interior joins learner least less meet Nature necessary opposite parallel parallelogram pass pentagon point of contact Problem produced proof PROPOSITION PROPOSITION VIII PROPOSITION XV Proved by showing READINGS rectangle contained right angles right line right Zs segment shows the supposition sides similarly square Steps straight line Suppose supposition is false Theorem touch triangle VOLUME whole whole line YOUNG

### Populære avsnitt

Side 24 - If two triangles have two angles of the [one equal to two angles of the other, each to each, and one side equal to one side, namely, either t}le sides adjacent to the equal...

Side 45 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.

Side 18 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.

Side 61 - From this it is manifest that the straight line which is drawn at right angles to the diameter of a circle from the extremity of it, touches the circle...

Side 37 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.

Side 76 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.

Side 77 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it, and if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square on GEOMETRY.

Side 72 - If a straight line touch a circle, and from the point of contact a straight line be drawn at right angles to the touching line, the centre of the circle shall be in that line.

Side 27 - If a straight line fall on two parallel straight lines, it makes the alternate angles equal to one another, and the exterior angle equal to the interior and opposite angle on the same side; and also the two interior angles on the same side together equal to two right angles.