A companion to Euclid: being a help to the understanding and remembering of the first four books. With a set of improved figures, and an original demonstration of the proposition called in Euclid the twelfth axiom, by a graduate |
Inni boken
Side 7
Take , for instance , the second problem .A learner would perhaps begin by
drawing the larger circle , then the smaller one , and so on ; and consider it
immaterial with what part he began , so that his figure , when completed , was
similar to that ...
Take , for instance , the second problem .A learner would perhaps begin by
drawing the larger circle , then the smaller one , and so on ; and consider it
immaterial with what part he began , so that his figure , when completed , was
similar to that ...
Side 11
Problem . From a given point to draw a straight line equal to a given straight line .
Steps of the Demonstration . The 1st thing to be proved is that BG = BC ,
PROPOSITION III . Problem . From the greater of two. that D L = D G that AL = BG
or BC ...
Problem . From a given point to draw a straight line equal to a given straight line .
Steps of the Demonstration . The 1st thing to be proved is that BG = BC ,
PROPOSITION III . Problem . From the greater of two. that D L = D G that AL = BG
or BC ...
Side 17
Euclides. PROPOSITION X . Problem . To bisect a given finite straight line ; that is
, to divide it into two equal parts . : B PROPOSITION XI . Problem . To draw a
straight line at right angles to a given straight line from a given point in the same .
Euclides. PROPOSITION X . Problem . To bisect a given finite straight line ; that is
, to divide it into two equal parts . : B PROPOSITION XI . Problem . To draw a
straight line at right angles to a given straight line from a given point in the same .
Side 78
PROPOSITION I . Problem . In a given circle to place a straight line , not greater
than the diameter of the circle . DProved by showing , from the construction , that
AC = Ce ; and CE = D . PROPOSITION II . Problem . In a given circle to inscribe a
...
PROPOSITION I . Problem . In a given circle to place a straight line , not greater
than the diameter of the circle . DProved by showing , from the construction , that
AC = Ce ; and CE = D . PROPOSITION II . Problem . In a given circle to inscribe a
...
Side 80
Proposition V . To describe a circle about a given Problem . triangle . Steps of the
Demonstration . ( In the construction of the figure , prove that the perpendiculars
DF and EF will meet , as in F ) . ai 1 . Prove that ( in As ADF , BDF ) base BF ...
Proposition V . To describe a circle about a given Problem . triangle . Steps of the
Demonstration . ( In the construction of the figure , prove that the perpendiculars
DF and EF will meet , as in F ) . ai 1 . Prove that ( in As ADF , BDF ) base BF ...
Hva folk mener - Skriv en omtale
Vi har ikke funnet noen omtaler på noen av de vanlige stedene.
Vanlige uttrykk og setninger
alternate angle contained angle equal applied Argument ad absurdum base bisect BOOK centre circumference coincides construction Demonstration described diameter directed divided draw drawn Edition Engravings equal equiangular equilateral Euclid extremities fall figure given circle given point given rectilineal given straight line greater HISTORY impossible inscribe interior joins learner least less meet Nature necessary opposite parallel parallelogram pass pentagon point of contact Problem produced proof PROPOSITION PROPOSITION VIII PROPOSITION XV Proved by showing READINGS rectangle contained right angles right line right Zs segment shows the supposition sides similarly square Steps straight line Suppose supposition is false Theorem touch triangle VOLUME whole whole line YOUNG
Populære avsnitt
Side 24 - If two triangles have two angles of the [one equal to two angles of the other, each to each, and one side equal to one side, namely, either t}le sides adjacent to the equal...
Side 45 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 18 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 61 - From this it is manifest that the straight line which is drawn at right angles to the diameter of a circle from the extremity of it, touches the circle...
Side 37 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 76 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Side 77 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it, and if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square on GEOMETRY.
Side 72 - If a straight line touch a circle, and from the point of contact a straight line be drawn at right angles to the touching line, the centre of the circle shall be in that line.
Side 27 - If a straight line fall on two parallel straight lines, it makes the alternate angles equal to one another, and the exterior angle equal to the interior and opposite angle on the same side; and also the two interior angles on the same side together equal to two right angles.