Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, a Treatise of the Nature and Arithmetic of Logarithms; Likewise Another of the Elements of Plane and Spherical Trigonometry; with a Preface, Shewing the Usefulness and Excellency of this WorkW. Strahan, 1772 - 399 sider |
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Resultat 1-5 av 22
Side 278
... Cofine : The other Segment BE , which is intercepted between the Right Sine and the Periphery , is called a Verfed Sine , and fometimes a Sagitta . And , if the Right Line CG be produced from the Centre C , thro ' one End D of the Arc ...
... Cofine : The other Segment BE , which is intercepted between the Right Sine and the Periphery , is called a Verfed Sine , and fometimes a Sagitta . And , if the Right Line CG be produced from the Centre C , thro ' one End D of the Arc ...
Side 279
... Cofine , T. a Tan- gent , and Cot . a Cotangent ; alfo ACq fignifies the Square of the Right Line A C ; and the Marks or Cha- racters + , - ,, :: , and √ , are , feverally , used to fignify Addition , Subtraction , Equality ...
... Cofine , T. a Tan- gent , and Cot . a Cotangent ; alfo ACq fignifies the Square of the Right Line A C ; and the Marks or Cha- racters + , - ,, :: , and √ , are , feverally , used to fignify Addition , Subtraction , Equality ...
Side 280
... Cofine and Radius . Therefore DE , EB , being given , in the Right - angled Triangle DBE , there will be given D B , whofe Half DM is the Sine of the Arc DL the Arc B D. PROPOSITION IV . PROBLEM . The Sine B M of the Arc BL being given ...
... Cofine and Radius . Therefore DE , EB , being given , in the Right - angled Triangle DBE , there will be given D B , whofe Half DM is the Sine of the Arc DL the Arc B D. PROPOSITION IV . PROBLEM . The Sine B M of the Arc BL being given ...
Side 281
... Cofine of the Arc F D , which accordingly is given , and draw OP thro ' O parallel to DK ; also let OM , GE , be drawn parallel to CB : Then , because the Triangles CDK , COP , CHI , FOH , FOM , are equiangular ; in the firft Place CD ...
... Cofine of the Arc F D , which accordingly is given , and draw OP thro ' O parallel to DK ; also let OM , GE , be drawn parallel to CB : Then , because the Triangles CDK , COP , CHI , FOH , FOM , are equiangular ; in the firft Place CD ...
Side 282
... Cofine of 15 Degrees , as the Sine of 1 Degree is to the Differ- ence of the Sines of 14 Degrees , and 16 Degrees ... Cofine of 30 Degrees , as I to ✓ 3 . See FIG . of the DEFINITIONS . Let BD be an Arc of 30 Degrees : Rad . Tan ...
... Cofine of 15 Degrees , as the Sine of 1 Degree is to the Differ- ence of the Sines of 14 Degrees , and 16 Degrees ... Cofine of 30 Degrees , as I to ✓ 3 . See FIG . of the DEFINITIONS . Let BD be an Arc of 30 Degrees : Rad . Tan ...
Andre utgaver - Vis alle
Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Ingen forhåndsvisning tilgjengelig - 2018 |
Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Ingen forhåndsvisning tilgjengelig - 2017 |
Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
A B C adjacent Angles alfo equal alſo Angle ABC Baſe becauſe bifected Centre Circle ABCD Circumference Cofine Cone confequently Coroll Cylinder defcribed demonftrated Diameter Diſtance drawn thro equal Angles equiangular Equimultiples faid fame Altitude fame Multiple fame Plane fame Proportion fame Reaſon fecond fhall be equal fimilar fince firft folid Parallelepipedon fome fore ftand fubtending given Right Line Gnomon greater join leffer lefs likewife Logarithm Magnitudes Meaſure Number oppofite parallel Parallelogram perpendicular Polygon Prifm Prop PROPOSITION Pyramid Quadrant Ratio Reafon Rectangle Rectangle contained remaining Angle Right Angles Right Line A B Right-lined Figure Segment ſhall Sides A B Sine Square Subtangent thefe THEOREM thofe thoſe tiple Triangle ABC Unity Vertex the Point Wherefore whofe Bafe whoſe
Populære avsnitt
Side 195 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 165 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Side 169 - Equal parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles...
Side xxii - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Side 54 - If a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Side 123 - GB is equal to E, and HD to F; GB and HD together are equal to E and F together : wherefore as many magnitudes as...
Side 215 - CD; therefore AC is a parallelogram. In like manner, it may be proved that each of the figures CE, FG, GB, BF, AE, is a parallelogram...
Side 196 - ABC, and they are both in the same plane, which is impossible ; therefore the straight line BC is not above the plane in which are BD and BE: wherefore, the three straight lines BC, BD, BE are in one and the same plane. Therefore, if three straight lines, &c.
Side 161 - And because HE is parallel to KC, one of the sides of the triangle DKC, as CE to ED, so is...
Side 207 - A plane is perpendicular to a plane, when the straight lines drawn in one of the planes perpendicular to the common section of the two planes, are perpendicular to the other plane. V. The inclination of a straight line to a plane...