 | George Roberts Perkins - 1841 - 274 sider
...right of the TRIAL DIVISOR ; the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR,... | |
 | William Scott - 1844 - 568 sider
...figure of the root) to the first figure, and also to the divisor. Multiply the new divisor thus formed by the second figure of the root, and subtract the product from the number composed of the first remainder and second period. To this, the second remainder, annex the... | |
 | Francis Henney Smith - 1845 - 710 sider
...figure of the root. IV. Place it in the root, and also on the right of the divisor. Multiply the entire divisor by the second figure of the root, and subtract the product from the dividend. To the remainder bring down the next period. V. Double the whole of the root found for a new divisor,... | |
 | Francis Henney Smith - 1845 - 300 sider
...figure of the root. IV. Place it in the root, and also on the right of the divisor. Multiply the entire divisor by the second figure of the root, and subtract the product from the dividend. To the remainder bring down the next period. V; Double the whole of the root found for a new divisor,... | |
 | Charles Davies - 1845 - 382 sider
...first figure of the root and the sum ; in the last column will be the second divisor, which multiply by the second figure of the root and subtract the product from the second dividend. V. Tlie next trial divisor, the, next figure of the root, and the true divisor, are... | |
 | George Roberts Perkins - 1849 - 344 sider
...right of the TRIAL DIVISOR ; the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period for a SECOND DIVIDEND. operate as before, until all the... | |
 | George Roberts Perkins - 1850 - 356 sider
...two places to the right, to the last term of the 2d column. Again, multiply this last result by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period for a NEW DIVIDEND. Proceed with this second figure of the... | |
 | William Scott - 1854 - 232 sider
...root) to the first figure of the root, and also to the divisor. Multiply the new divisor, thus formed, by the second figure of the root, and subtract the product from the number composed of the first remainder and second period. To this remainder annex the third period... | |
 | James Stewart Eaton - 1857 - 376 sider
...root and also at the right of the trial divisor, and so form the TRUE DIVISOR. 5. Multiply the true divisor by the second figure of the root and subtract the product from the dividend. 6. To the remainder annex the next period for a new dividend, and, having doubled the part of the root... | |
 | 1865 - 580 sider
...4800, and add them together. The resulting sum, 5169, is the first real divisor. We next multiply the divisor by the second figure of the root, and subtract the product 15507, as in long division, bringing down the next period 568. To obtain the next real divisor we proceed... | |
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Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. 
