The Young Geometrician's Companion: Being A New and Comprehensive Course of Practical Geometry ... Containing. An easy introduction to decimal arithmetic .... Such definitions, axioms, problems, theorems, and characters, as necessarily lead to the knowledge of this science. Planometry, or the mensuration of superficies. Stereometry, ot he mensuration of solids. The sections of a cone .... The Platonic bodies ... To which is added a collection of problems shewing that lines and angles may be divided in infinitum; that superficies and solids may be so cut as to appear considerably augmented; and, that the famous problem of Archimedes, of moving the earth, is capable of an easy and accurate demonstration, Volum 6S. Crowder, 1787 - 240 sider |
Inni boken
Resultat 1-5 av 6
Side vii
... Rhombus , each of whose Sides shall be equal to a given Right Line 84 To divide the Circumference of a Circle 85 To draw a Circle through three given Points 88 To draw a Tangent to a given Circle 89 To defcribe a Geometrical Oval , the ...
... Rhombus , each of whose Sides shall be equal to a given Right Line 84 To divide the Circumference of a Circle 85 To draw a Circle through three given Points 88 To draw a Tangent to a given Circle 89 To defcribe a Geometrical Oval , the ...
Side viii
... Rhombus To find the Area of a Rhomboides 112 113 114 To find the Area of a Triangle 115 To find the Area of an Oblique Triangle 116 To find the Area of a Trapezium 117 To find the Area of a Regular Polygon 118 To find the Area of a ...
... Rhombus To find the Area of a Rhomboides 112 113 114 To find the Area of a Triangle 115 To find the Area of an Oblique Triangle 116 To find the Area of a Trapezium 117 To find the Area of a Regular Polygon 118 To find the Area of a ...
Side 83
... is equally useful to Sur- veyors , Architects , and Mechanics . Problem 14 . To make a Rhombus , each of E6 Pro- PRACTICAL GEOMETRY . 83 To make a Parallelogram whose Length and Breadth shall be equal to two Right Lines given.
... is equally useful to Sur- veyors , Architects , and Mechanics . Problem 14 . To make a Rhombus , each of E6 Pro- PRACTICAL GEOMETRY . 83 To make a Parallelogram whose Length and Breadth shall be equal to two Right Lines given.
Side 84
... Rhombus , each of whose Sides shall be equal to a given Right Line ; and whose acute Angle shall also be equal to an Angle given . Let the Line given be A B , and the Acute Angle CA B , to delineate a Rhombus , whose Sides and Acute ...
... Rhombus , each of whose Sides shall be equal to a given Right Line ; and whose acute Angle shall also be equal to an Angle given . Let the Line given be A B , and the Acute Angle CA B , to delineate a Rhombus , whose Sides and Acute ...
Side 112
... × 12.75 = 325.125 , the Area in Inches . * The Reason of this Rule appears from the ist Figure , because this is only a long Square . Problem 3 . To find the Area of a Rhombus Pro- 112 PRACTICAL GEOMETRY To find the Area of a Parallelogram.
... × 12.75 = 325.125 , the Area in Inches . * The Reason of this Rule appears from the ist Figure , because this is only a long Square . Problem 3 . To find the Area of a Rhombus Pro- 112 PRACTICAL GEOMETRY To find the Area of a Parallelogram.
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Vanlige uttrykk og setninger
12 Inches acroſs alſo Anſwer Axis Bafe Baſe Baſe A B becauſe Breadth called Caſk Center Chord Circle Circum Circumference Compaſſes Cone conſequently Conſtruction Crample Cube Root Cyphers deſcribe the Arch Dimenſions Diſtance divide Dividend Divifor draw the Line Ellipsis Example fame Feet Figure find the Area find the Solidity Firſt Fruftum fubtract Geometrical give the Solidity given Number half Hexaëdron Hyperbola Icofaëdron Inches interſecting itſelf Lastly Latus Rectum leſs Let ABCD Line A B Line given Magic Squares Mean Proportional meaſure Middle multiplied muſt Operation Parabola Parallelogram Platonic Solids Point Problem Pyramid Quotient Reſolvend Rhombus Right Angle Right Line Rule ſame Segment ſet one Foot ſeveral ſhould ſmall Solid Content Solidity required ſome Spheroid ſquare Square Root ſtanding Stereometry ſuch Superficial Content Suppoſe Theorem theſe thoſe Tranſverſe Diameter Trapezium Triangle Uſe Vertex Vulgar Fraction whole Number whoſe whoſe Baſe whoſe Sides
Populære avsnitt
Side 95 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. Let AB be the given straight line; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to thcsquare of the other part.
Side 181 - Rule: To twice the square of the middle diameter, add the square of the diameter of...
Side 33 - Multiply the two given numbers together, and extract the square root of the product, which root will be the mean proportional sought. EXAMPLES. (1) What is the mean proportional between 4 and 9 ? (2) What is the mean proportional between 16 and 36?
Side 149 - For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required.
Side 120 - As 7 is to 22, so is the diameter to the circumference. Or as 113 is to 355, so is the diameter to the circumference. • Or as 1 is to 3.1416, so is the diameter to the circumferenc".
Side 138 - This error, though it. is b«! small, when the depth and breadth are pretty near equal, yet if the difference...
Side 175 - To find the solidity of a spheroid. — Multiply the square of the revolving axe by the fixed axe, and this product again by -5236, and it will give the solidity required.
Side 213 - DF'E. Hence the entire area of the (!i GP cycloid is equal to three times the area of the generating circle.
Side 133 - To find the side of a square equal in area to any given superfices.
Side 28 - Divifion, write the anfwer in the Quotient, and alfo on the right hand of the Divifor...