The Young Geometrician's Companion: Being A New and Comprehensive Course of Practical Geometry ... Containing. An easy introduction to decimal arithmetic .... Such definitions, axioms, problems, theorems, and characters, as necessarily lead to the knowledge of this science. Planometry, or the mensuration of superficies. Stereometry, ot he mensuration of solids. The sections of a cone .... The Platonic bodies ... To which is added a collection of problems shewing that lines and angles may be divided in infinitum; that superficies and solids may be so cut as to appear considerably augmented; and, that the famous problem of Archimedes, of moving the earth, is capable of an easy and accurate demonstration, Volum 6S. Crowder, 1787 - 240 sider |
Inni boken
Resultat 1-5 av 5
Side viii
... Trapezium 117 To find the Area of a Regular Polygon 118 To find the Area of a Circle 119 To find the Area of a Circle by another Method 120 To find the Area of a Circle , Semi - circle , or Quadrant 123 To find the Area of a Sector of a ...
... Trapezium 117 To find the Area of a Regular Polygon 118 To find the Area of a Circle 119 To find the Area of a Circle by another Method 120 To find the Area of a Circle , Semi - circle , or Quadrant 123 To find the Area of a Sector of a ...
Side 97
... Trapezium or any other Right Lined Figure be reduced to a Triangle equal to it . B This Problem is useful in Surveying , to find the Con- tent of an irregular Piece of Ground at one Operation ; without dividing it into many Triangles ...
... Trapezium or any other Right Lined Figure be reduced to a Triangle equal to it . B This Problem is useful in Surveying , to find the Con- tent of an irregular Piece of Ground at one Operation ; without dividing it into many Triangles ...
Side 116
... Reason is because every oblique Triangle is equal to Half its Circumfcribing Parallelogram , as in the last Problem . Problem 7 . To find the Area of a Trapezium Pra 116 PRACTICAL GEOMETRY . To find the Area of an Oblique Triangle.
... Reason is because every oblique Triangle is equal to Half its Circumfcribing Parallelogram , as in the last Problem . Problem 7 . To find the Area of a Trapezium Pra 116 PRACTICAL GEOMETRY . To find the Area of an Oblique Triangle.
Side 117
... Trapezium . Def . A Trapezium consists of four unequal Sides , and four unequal Angles . Rule . * Add the two Perpendiculars together , and multiply that Sum by Half the Diagonal ; ( or multiply the Diagonal by Half the Sum of the ...
... Trapezium . Def . A Trapezium consists of four unequal Sides , and four unequal Angles . Rule . * Add the two Perpendiculars together , and multiply that Sum by Half the Diagonal ; ( or multiply the Diagonal by Half the Sum of the ...
Side 132
... Trapezium , one Triangle , or rather into three Triangles , the Areas and will be as under . Area of the Triangle BCD is 187 Area of the Triangle ABD is 204 Area of the Triangle ADE is 105 Area of the whole Figure 496 } Inches . Note ...
... Trapezium , one Triangle , or rather into three Triangles , the Areas and will be as under . Area of the Triangle BCD is 187 Area of the Triangle ABD is 204 Area of the Triangle ADE is 105 Area of the whole Figure 496 } Inches . Note ...
Innhold
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Vanlige uttrykk og setninger
12 Inches acroſs alſo Anſwer Axis Bafe Baſe Baſe A B becauſe Breadth called Caſk Center Chord Circle Circum Circumference Compaſſes Cone conſequently Conſtruction Crample Cube Root Cyphers deſcribe the Arch Dimenſions Diſtance divide Dividend Divifor draw the Line Ellipsis Example fame Feet Figure find the Area find the Solidity Firſt Fruftum fubtract Geometrical give the Solidity given Number half Hexaëdron Hyperbola Icofaëdron Inches interſecting itſelf Lastly Latus Rectum leſs Let ABCD Line A B Line given Magic Squares Mean Proportional meaſure Middle multiplied muſt Operation Parabola Parallelogram Platonic Solids Point Problem Pyramid Quotient Reſolvend Rhombus Right Angle Right Line Rule ſame Segment ſet one Foot ſeveral ſhould ſmall Solid Content Solidity required ſome Spheroid ſquare Square Root ſtanding Stereometry ſuch Superficial Content Suppoſe Theorem theſe thoſe Tranſverſe Diameter Trapezium Triangle Uſe Vertex Vulgar Fraction whole Number whoſe whoſe Baſe whoſe Sides
Populære avsnitt
Side 95 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. Let AB be the given straight line; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to thcsquare of the other part.
Side 181 - Rule: To twice the square of the middle diameter, add the square of the diameter of...
Side 33 - Multiply the two given numbers together, and extract the square root of the product, which root will be the mean proportional sought. EXAMPLES. (1) What is the mean proportional between 4 and 9 ? (2) What is the mean proportional between 16 and 36?
Side 149 - For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required.
Side 120 - As 7 is to 22, so is the diameter to the circumference. Or as 113 is to 355, so is the diameter to the circumference. • Or as 1 is to 3.1416, so is the diameter to the circumferenc".
Side 138 - This error, though it. is b«! small, when the depth and breadth are pretty near equal, yet if the difference...
Side 175 - To find the solidity of a spheroid. — Multiply the square of the revolving axe by the fixed axe, and this product again by -5236, and it will give the solidity required.
Side 213 - DF'E. Hence the entire area of the (!i GP cycloid is equal to three times the area of the generating circle.
Side 133 - To find the side of a square equal in area to any given superfices.
Side 28 - Divifion, write the anfwer in the Quotient, and alfo on the right hand of the Divifor...