The Young Geometrician's Companion: Being A New and Comprehensive Course of Practical Geometry ... Containing. An easy introduction to decimal arithmetic .... Such definitions, axioms, problems, theorems, and characters, as necessarily lead to the knowledge of this science. Planometry, or the mensuration of superficies. Stereometry, ot he mensuration of solids. The sections of a cone .... The Platonic bodies ... To which is added a collection of problems shewing that lines and angles may be divided in infinitum; that superficies and solids may be so cut as to appear considerably augmented; and, that the famous problem of Archimedes, of moving the earth, is capable of an easy and accurate demonstration, Volum 6S. Crowder, 1787 - 240 sider |
Inni boken
Resultat 1-5 av 58
Side vi
... divide a Right Line into two equal Parts To erect a Perpendicular on any Point in a Right Line 71 given 72 To erect a Perpendicular on the End of a Right Line 73 To let fall a Perpendicular upon a Right Line given 74 To draw a Line ...
... divide a Right Line into two equal Parts To erect a Perpendicular on any Point in a Right Line 71 given 72 To erect a Perpendicular on the End of a Right Line 73 To let fall a Perpendicular upon a Right Line given 74 To draw a Line ...
Side vii
... divide an Angle given into two equal Parts 77 To make an Angle equal to an Angle given 78 To divide a given Line into any Number of equal Parts 79 To make an Equilateral Triangle 80 To make a Triangle whose Sides shall be equal to three ...
... divide an Angle given into two equal Parts 77 To make an Angle equal to an Angle given 78 To divide a given Line into any Number of equal Parts 79 To make an Equilateral Triangle 80 To make a Triangle whose Sides shall be equal to three ...
Side x
... divide a given Line into an infinite Number of 203 204 Parts 205 To shew that an Angle , as well as a Line , may be con- tinually diminished , and yet never be reduced to nothing 206 To reduce a Parallelogram to a Square equivalent in ...
... divide a given Line into an infinite Number of 203 204 Parts 205 To shew that an Angle , as well as a Line , may be con- tinually diminished , and yet never be reduced to nothing 206 To reduce a Parallelogram to a Square equivalent in ...
Side 9
... Divide 4.6732 by .23 .23 ) 4.6736 ( 20.32 Answer . 40 ما 73 69 - 46 . 46 ..... Here the Decimal Parts in the Dividend exceed those in the Divisor by two ; we therefore cut off two Places for Decimals in the Quotient . By this Means we ...
... Divide 4.6732 by .23 .23 ) 4.6736 ( 20.32 Answer . 40 ما 73 69 - 46 . 46 ..... Here the Decimal Parts in the Dividend exceed those in the Divisor by two ; we therefore cut off two Places for Decimals in the Quotient . By this Means we ...
Side 10
... Divide .6474 by 73 . 73 ) .6474 ( .0088 the Answer . 584 634 584 ( 50 ) Here the Quotient is 88 ; but as there are four Places of Decimals in the Dividend , and none in the Divisor , four Places must be cut off in the Quotient . We ...
... Divide .6474 by 73 . 73 ) .6474 ( .0088 the Answer . 584 634 584 ( 50 ) Here the Quotient is 88 ; but as there are four Places of Decimals in the Dividend , and none in the Divisor , four Places must be cut off in the Quotient . We ...
Innhold
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Vanlige uttrykk og setninger
12 Inches acroſs alſo Anſwer Axis Bafe Baſe Baſe A B becauſe Breadth called Caſk Center Chord Circle Circum Circumference Compaſſes Cone conſequently Conſtruction Crample Cube Root Cyphers deſcribe the Arch Dimenſions Diſtance divide Dividend Divifor draw the Line Ellipsis Example fame Feet Figure find the Area find the Solidity Firſt Fruftum fubtract Geometrical give the Solidity given Number half Hexaëdron Hyperbola Icofaëdron Inches interſecting itſelf Lastly Latus Rectum leſs Let ABCD Line A B Line given Magic Squares Mean Proportional meaſure Middle multiplied muſt Operation Parabola Parallelogram Platonic Solids Point Problem Pyramid Quotient Reſolvend Rhombus Right Angle Right Line Rule ſame Segment ſet one Foot ſeveral ſhould ſmall Solid Content Solidity required ſome Spheroid ſquare Square Root ſtanding Stereometry ſuch Superficial Content Suppoſe Theorem theſe thoſe Tranſverſe Diameter Trapezium Triangle Uſe Vertex Vulgar Fraction whole Number whoſe whoſe Baſe whoſe Sides
Populære avsnitt
Side 95 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. Let AB be the given straight line; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to thcsquare of the other part.
Side 181 - Rule: To twice the square of the middle diameter, add the square of the diameter of...
Side 33 - Multiply the two given numbers together, and extract the square root of the product, which root will be the mean proportional sought. EXAMPLES. (1) What is the mean proportional between 4 and 9 ? (2) What is the mean proportional between 16 and 36?
Side 149 - For the surface of a segment or frustum, multiply the whole circumference of the sphere by the height of the part required.
Side 120 - As 7 is to 22, so is the diameter to the circumference. Or as 113 is to 355, so is the diameter to the circumference. • Or as 1 is to 3.1416, so is the diameter to the circumferenc".
Side 138 - This error, though it. is b«! small, when the depth and breadth are pretty near equal, yet if the difference...
Side 175 - To find the solidity of a spheroid. — Multiply the square of the revolving axe by the fixed axe, and this product again by -5236, and it will give the solidity required.
Side 213 - DF'E. Hence the entire area of the (!i GP cycloid is equal to three times the area of the generating circle.
Side 133 - To find the side of a square equal in area to any given superfices.
Side 28 - Divifion, write the anfwer in the Quotient, and alfo on the right hand of the Divifor...