## The synoptical Euclid; being the first four books of Euclid's Elements of geometry, with exercises, by S.A. Good |

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Resultat 1-5 av 18

Side 9

... and the triangle ÅBC to the triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal , each to each , viz . the angle ABC to the angle DEF , and the

... and the triangle ÅBC to the triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal , each to each , viz . the angle ABC to the angle DEF , and the

**angle ACB**to DFE . A C B For if the triangle ... Side 10

The angles at the base of an isosceles triangle are equal to one another ; and if the equal sides be produced ... AC , be produced to D and E , the angle ABC shall be equal to the

The angles at the base of an isosceles triangle are equal to one another ; and if the equal sides be produced ... AC , be produced to D and E , the angle ABC shall be equal to the

**angle ACB**, and the angle CBD to the angle BCE . Side 11

And it has also been proved that the angle FBC is equal to the angle GCB , which are the angles upon the other side of ... Let ABC be a triangle having the angle ABC equal to the

And it has also been proved that the angle FBC is equal to the angle GCB , which are the angles upon the other side of ... Let ABC be a triangle having the angle ABC equal to the

**angle ACB**; the side AB is also equal to the side AC . Side 12

The

The

**angle**BDC is equal to the**angle**BCD ; but it has been demonstrated to be greater than it , which is impossible . But if one of the vertices , as D , be within the other triangle**ACB**; produce AC , AD to E , F ; therefore because AC ... Side 14

the

the

**angle ACB**by the straight line CD . AB is cut into two equal parts in the point D. D B A Because AC is equal to CB , and CD common to the two triangles ACD , BCD ; 1 . The two sides AC , CD are equal to BC , CD , each to each ...### Hva folk mener - Skriv en omtale

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The Synoptical Euclid; Being the First Four Books of Euclid's Elements of ... Uten tilgangsbegrensning - 1854 |

### Vanlige uttrykk og setninger

ABCD AC is equal AF is equal angle ABC angle ACB angle BAC angle BCD angle equal base base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line given triangle gnomon greater impossible inscribed join less Let ABC likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle required to describe right angles segment semicircle shown sides square of AC straight line AC THEOREM touches the circle triangle ABC twice the rectangle wherefore whole

### Populære avsnitt

Side 26 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal...

Side 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.

Side 32 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Side 1 - A plane superficies is that in which any two points being taken, the straight line between them lies wholly in that superficies. vm. "A plane angle is the inclination of two lines to one another in a plane, which meet together, but are not in the same direction.

Side 97 - If from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.

Side 7 - AB; but things which are equal to the same are equal to one another...

Side 14 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.

Side 53 - IF a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part.

Side 41 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.

Side 52 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced...