## The synoptical Euclid; being the first four books of Euclid's Elements of geometry, with exercises, by S.A. Good |

### Inni boken

Side 7

To describe an equilateral triangle upon a given finite straight line . Let AB be the given straight line ; it is

To describe an equilateral triangle upon a given finite straight line . Let AB be the given straight line ; it is

**required to describe**an equilateral triangle upon it . From the centre A , at the distance AB , describe ( Postulate 3. ) ... Side 8

It is

It is

**required**to cut off from AB , the greater , a part equal to C , the less . From the point 4 , draw ( I. 2. ) the straight line AD equal to C ; and from the centre A , and at the distance AD ,**describe**( Post . 3. ) ... Side 13

Let BAC be the given rectilineal angle , it is

Let BAC be the given rectilineal angle , it is

**required**to bisect it . Take any point Din AB , and from AC cut ( I. 3. ) off AE equal to AD ; join DE , and upon it , on the side remote from 4 ,**describe**( I. 1. ) ... Side 14

Let AB be the given straight line ; it is

Let AB be the given straight line ; it is

**required**to divide it into two equal parts .**Describe**( I. 1. ) upon it an equilateral triangle ABC , and bisect ( I. 9. ) the angle ACB by the straight line CD . AB is cut into two equal parts ... Side 16

It is

It is

**required**to draw a straight line perpendicular to AB from the point C. Take any point Dupon the other side of AB , and from the centre C , at the distance CD ,**describe**( Post . 3. ) the circle EGF meeting AB in F , G ; and bisect ...### Hva folk mener - Skriv en omtale

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The Synoptical Euclid; Being the First Four Books of Euclid's Elements of ... EUCLID.,Samuel A. GOOD Uten tilgangsbegrensning - 1854 |

The Synoptical Euclid; Being the First Four Books of Euclid's Elements of ... EUCLID.,Samuel A. GOOD Uten tilgangsbegrensning - 1854 |

### Vanlige uttrykk og setninger

ABCD AC is equal AF is equal angle ABC angle ACB angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles equal Constr exterior angle extremity fall figure four given circle given point given straight line given triangle greater impossible inscribed join less Let ABC likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle required to describe right angles segment semicircle shown side BC sides square of AC straight line AC touches the circle triangle ABC twice the rectangle wherefore whole

### Populære avsnitt

Side 26 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal...

Side 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.

Side 32 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Side 1 - A plane superficies is that in which any two points being taken, the straight line between them lies wholly in that superficies. vm. "A plane angle is the inclination of two lines to one another in a plane, which meet together, but are not in the same direction.

Side 97 - If from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.

Side 7 - AB; but things which are equal to the same are equal to one another...

Side 14 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.

Side 53 - IF a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part.

Side 41 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.

Side 52 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced...