Elements of GeometryHilliard and Metcalf, at the University Press, 1819 - 208 sider |
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Side v
... drawn between two points from the shortest line which measures the distance of these same points . I have preferred , in order not to render the introduction to geometry too difficult , to sacrifice something of the exactness at which I ...
... drawn between two points from the shortest line which measures the distance of these same points . I have preferred , in order not to render the introduction to geometry too difficult , to sacrifice something of the exactness at which I ...
Side 5
... drawn from A to B , which is impos- sible ( 25 ) . Now let us suppose , if it be possible , that the lines , when produced , separate from each other at a point C , the one becoming CD , and the other CE . At the point C , let CF be drawn ...
... drawn from A to B , which is impos- sible ( 25 ) . Now let us suppose , if it be possible , that the lines , when produced , separate from each other at a point C , the one becoming CD , and the other CE . At the point C , let CF be drawn ...
Side 9
... Draw the straight line AD from the vertex A to the point D the middle of the base BC ; the two triangles ABD , ADC , will have the three sides of the one , equal to the three sides of the other , each to each , namely , AD common to ...
... Draw the straight line AD from the vertex A to the point D the middle of the base BC ; the two triangles ABD , ADC , will have the three sides of the one , equal to the three sides of the other , each to each , namely , AD common to ...
Side 10
... drawn from the vertex of an isosceles triangle , to the middle of the base , is perpendicular to that base , and ... Draw CD making the angle BCD = B. In the triangle BDC , BD is equal to DC ( 48 ) ; but AD + DC > AC , and AD + DC ...
... drawn from the vertex of an isosceles triangle , to the middle of the base , is perpendicular to that base , and ... Draw CD making the angle BCD = B. In the triangle BDC , BD is equal to DC ( 48 ) ; but AD + DC > AC , and AD + DC ...
Side 11
... drawn to that line . Demonstration . If it be possible , let there be two AB and AC ; produce one of them AB , so that ... draw two perpendiculars to that line ; for , if CD and CE were these two perpendiculars , the angle DCB would be a ...
... drawn to that line . Demonstration . If it be possible , let there be two AB and AC ; produce one of them AB , so that ... draw two perpendiculars to that line ; for , if CD and CE were these two perpendiculars , the angle DCB would be a ...
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Vanlige uttrykk og setninger
ABCD adjacent angles algebraic algebraic quantities altitude angle ACB base centre chord circ circle circular sector circumference coefficient common divisor cone consequently contains Corollary cube cylinder Demonstration denominator denoted diameter divided dividend division equal equivalent evident example exponent expression factors figure fraction frustum given gives greater greatest common divisor homologous sides inscribed less letters logarithm manner measure multiplied obtain parallel parallelogram parallelopiped perpendicular plane MN polyedron preceding prism proportion proposed equation proposition quotient radical sign radii radius ratio rectangle reduced regular polygon remainder result right angles Scholium side BC similar solid angle sphere spherical square root straight line substitute subtract suppose term THEOREM third tion triangle ABC triangular pyramids unity unknown quantity vertex whence
Populære avsnitt
Side 63 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Side 7 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Side 151 - THE sphere is a solid terminated by a curve surface, all the points of which are equally distant from a point within, called the centre.
Side 76 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 25 - Two equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre.
Side 52 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Side 160 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.
Side 203 - In every triangle the sum of the three angles is equal to two right angles.
Side 162 - In any spherical triangle, the greater side is opposite the greater angle ; and conversely, the greater angle is opposite the greater side.
Side 141 - If a pyramid is cut by a plane parallel to its base, the...