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Bøker Bok 110 av 16Adding to the trial-divisor 3 ab, that is, three times the product of the first term...
" Adding to the trial-divisor 3 ab, that is, three times the product of the first term of the root by the second, and... "
Elements of Algebra - Side 135
av Silvestre François Lacroix - 1825 - 276 sider
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Elements of Geometry

Adrien Marie Legendre - 1819 - 208 sider
...square of its first term must necessarily form the first term, 16 a* c*, of the proposed quantity ; double the product of the first term of the root by the second must give the second term, 24 a* 6* c, of the proposed quantity ; and the square of the last term of...
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Elements of Geometry

Adrien Marie Legendre - 1825 - 224 sider
...in which the square I3 of the binomial m -\- n, produces, when developed, the terms m3 -f- 2mn + n3. Now, after we have arranged the proposed quantity,...the square of these two terms, represented here by I3 ; subtracting this square from the proposed quantity, we have for a remainder a quantity, which...
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An Elementary Treatise on Algebra: Designed to Facilitate the Comprehension ...

Ormsby MacKnight Mitchel - 1845 - 294 sider
...term of the root. To get the third term of the root, complete the divisor by adding to it three times the product of the first term of the root, by the second term, plus the square of the second term. Multiply the complete divisor by the second term of the root,...
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A Treatise on Algebra: Containing the Latest Improvements. Adapted to the ...

Charles William Hackley - 1846 - 503 sider
...root Gx 3 ; multiplying the whole of this quantity, 6r > —2z > , by — 2x* (which produces twice the product of the first term of the root by the second, together with the square of the second), and subtracting the product from the first remainder, we obtain...
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The University Algebra ...

John Fair Stoddard, William Downs Henkle - 1859 - 528 sider
...polynomial the square of the first term of the root, the first term of the remainder will be twice the product of the first term of the root by the second term of the root ; hence, we shall obtain the second term of the root by dividing the first term of...
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New Elementary Algebra: Designed for Common and High Schools and Academies

Shelton Palmer Sanford - 1879 - 332 sider
...the second term of the root. To form the complete divisor, we add to 362 (the trial divisor) 3 times the product of the first term of the root by the second, and also the square of the second. We shall then have 3b'+3bx + x2 as the complete divisor. Multiplying...
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A Complete Course in Algebra for Academies and High Schools

Webster Wells - 1885 - 349 sider
...term of the root, we obtain I, the second term. Adding to the trial-divisor Зa6, that is, three times the product of the first term of the root by the second, and 62, that is, the square of the last term of the root, completes the divisor, Зa2 + Зa6 + б2....
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A Complete Course in Algebra

Webster Wells - 1885
...term of the root, we obtain b, the second term. Adding to the trial-divisor 3ab, that is, three times the product of the first term of the root by the second, and 62, that is, the square of the last term of the root, completes the divisor, Зa8 + Зab + 62....
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A Complete Course in Algebra for Academies and High Schools

Webster Wells - 1885 - 349 sider
...root, 12 x4, we obtain — 3y as the second term of the root. Adding to the trial-divisor three times the product of the first term of the root by the second, — 18 x2y, and the square of the second term, 9т/2, completes the divisor, 12 ж* — I8x2y + 9ys....
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College Algebra: For the Use of Academies, Colleges, and Scientific Schools ...

Edward Albert Bowser - 1888 - 540 sider
...Also, since 3o26 + 3a62 + bs = (3a2 + Sab + b*)b, we add to the trial divisor Sab + &2, ie, three times the product of the first term of the root by the second, plus the square of the second, and we have the complete divisor 3a2 + Sab + b2 ; multiply this complete...
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