Mensuration for elementary and middle class schools1875 - 85 sider |
Inni boken
Resultat 1-5 av 28
Side 14
... Multiply 399 ac . 1 ro . 18 po . 27 yds . 8 ft . 36 inches by 98 . 19. Divide 76 ac . 0 ro . 4 po . 6 yds . 0 ft . 112 in . by 31 . 20 . " " 3687 c . yds . 1684 c . in . by 264 . LESSON III . - MEASUREMENT OF ANGLES . It has been ...
... Multiply 399 ac . 1 ro . 18 po . 27 yds . 8 ft . 36 inches by 98 . 19. Divide 76 ac . 0 ro . 4 po . 6 yds . 0 ft . 112 in . by 31 . 20 . " " 3687 c . yds . 1684 c . in . by 264 . LESSON III . - MEASUREMENT OF ANGLES . It has been ...
Side 19
... multiply two adjacent sides together . Thus , the area of A is 5 × 5 = 25 ; and that of B is 7 × 3 = 21 . The correctness of this rule may easily be tested experimentally ; the two figures above are divided out into a number of small ...
... multiply two adjacent sides together . Thus , the area of A is 5 × 5 = 25 ; and that of B is 7 × 3 = 21 . The correctness of this rule may easily be tested experimentally ; the two figures above are divided out into a number of small ...
Side 20
... multiply three numbers together , and then modify the result by introducing another factor so as to get the correct ... multiplying a and c , so that we must begin by ascertaining the length of the latter . Now by the preceding lesson we ...
... multiply three numbers together , and then modify the result by introducing another factor so as to get the correct ... multiplying a and c , so that we must begin by ascertaining the length of the latter . Now by the preceding lesson we ...
Side 22
... multiply the base by the perpendicular height . The In each of the above figures the area is AB × BE . reason of this rule is manifest ; for in each case the parallelo- gram ABCD is equal in area to the square or rectangle , ABEF ...
... multiply the base by the perpendicular height . The In each of the above figures the area is AB × BE . reason of this rule is manifest ; for in each case the parallelo- gram ABCD is equal in area to the square or rectangle , ABEF ...
Side 23
... multiply these together their product gives the area of the enclosing rectangle DBCF , which we know to be exactly double of the triangle ABC . ( Euc . I. 41 ) . The area of which can , therefore , readily be found by dividing by 2 . To ...
... multiply these together their product gives the area of the enclosing rectangle DBCF , which we know to be exactly double of the triangle ABC . ( Euc . I. 41 ) . The area of which can , therefore , readily be found by dividing by 2 . To ...
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Mensuration for Elementary and Middle Class Schools, Etc Henry Lewis (Principal of Culham College, Oxon.) Uten tilgangsbegrensning - 1875 |
Vanlige uttrykk og setninger
16 Maps acres ATLAS base breadth calculating called centre chains circle circular circumference cloth lettered consisting of 32 contains exactly convex surface cube cubic foot cubic ft diagonal diameter dimensions divided ellipse Euclid EXERCISES Fcap feet field find its area find its solidity find its volume find the area find the cost find the length Find the solid find the volume frustrum GEOGRAPHY Glasgow Gunter's chain heptagon Herriot Hill hypothenuse inscribed LESSON LL.D miles multiply half number of sides ordinates parallel parallelopiped pentagonal perpendicular distance perpendicular height Physical Map pickets poles radius rectangular regular polygon rhomboid rhombus right angle right-angled triangle rule sector segment side measures slant height small faces solid content solid figure sphere is equal square and rectangle square foot square pyramid square yard straight line surveyor trapezium trapezoid triangular prism vertex wedge World-shewing
Populære avsnitt
Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.
Side 29 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 23 - RULE. From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.