Mensuration for elementary and middle class schools1875 - 85 sider |
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Side 7
... Square and Rectangle , VI . The Rhombus and Rhomboid , · VII . Triangles , VIII . The Trapezoid , IX . The Trapezium , XI . The Circle , X. Regular Polygons , XII . Sectors and Segments of Circles , XIII . The Ellipse , PART III ...
... Square and Rectangle , VI . The Rhombus and Rhomboid , · VII . Triangles , VIII . The Trapezoid , IX . The Trapezium , XI . The Circle , X. Regular Polygons , XII . Sectors and Segments of Circles , XIII . The Ellipse , PART III ...
Side 11
... SQUARE MEASURE . 144 Square inches 9 Square feet 301 Square yards 40 Perches 4 Roods or 10 square chains 640 Acres 1 Square foot . 1 Square yard . 1 Square perch ( pole or rod ) . 1 Rood . 1 Acre . - 1 Square mile . Note . The name acre ...
... SQUARE MEASURE . 144 Square inches 9 Square feet 301 Square yards 40 Perches 4 Roods or 10 square chains 640 Acres 1 Square foot . 1 Square yard . 1 Square perch ( pole or rod ) . 1 Rood . 1 Acre . - 1 Square mile . Note . The name acre ...
Side 13
... square , each side of which measures 10 metres , and which therefore contains 100 square metres . The stere is a cubic metre . Instead of using these two names , the French generally speak of square and cubic metres , which is much ...
... square , each side of which measures 10 metres , and which therefore contains 100 square metres . The stere is a cubic metre . Instead of using these two names , the French generally speak of square and cubic metres , which is much ...
Side 17
... square upon the hypothenuse is equal to the sum of the squares upon the base and perpen- dicular . From this we get ... square of the base to that of the perpendicular , and take the square root . 2. To find either the base or the ...
... square upon the hypothenuse is equal to the sum of the squares upon the base and perpen- dicular . From this we get ... square of the base to that of the perpendicular , and take the square root . 2. To find either the base or the ...
Side 18
Henry Lewis (M.A.). Square of hypothenuse , = 652 Therefore square of perpendicular , Square of base , and perpendicular , = 562 = 4225 - 4225 . 3136 . 3136 = 1089 . = / 1089 = 33 . Answer , 33 feet . Example 2. - Find the hypothenuse of ...
Henry Lewis (M.A.). Square of hypothenuse , = 652 Therefore square of perpendicular , Square of base , and perpendicular , = 562 = 4225 - 4225 . 3136 . 3136 = 1089 . = / 1089 = 33 . Answer , 33 feet . Example 2. - Find the hypothenuse of ...
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Mensuration for Elementary and Middle Class Schools, Etc Henry Lewis (Principal of Culham College, Oxon.) Uten tilgangsbegrensning - 1875 |
Vanlige uttrykk og setninger
16 Maps acres ATLAS base breadth calculating called centre chains circle circular circumference cloth lettered consisting of 32 contains exactly convex surface cube cubic foot cubic ft diagonal diameter dimensions divided ellipse Euclid EXERCISES Fcap feet field find its area find its solidity find its volume find the area find the cost find the length Find the solid find the volume frustrum GEOGRAPHY Glasgow Gunter's chain heptagon Herriot Hill hypothenuse inscribed LESSON LL.D miles multiply half number of sides ordinates parallel parallelopiped pentagonal perpendicular distance perpendicular height Physical Map pickets poles radius rectangular regular polygon rhomboid rhombus right angle right-angled triangle rule sector segment side measures slant height small faces solid content solid figure sphere is equal square and rectangle square foot square pyramid square yard straight line surveyor trapezium trapezoid triangular prism vertex wedge World-shewing
Populære avsnitt
Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.
Side 29 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 23 - RULE. From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.