Cambridge Senate-house Problems and Riders for the Year 1860: With SolutionsMacmillan, 1860 - 198 sider |
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Side 1
... GE is twice the differ- ence between the two sides BE , ED . Whence the following construction . Take GE = half the given difference , describe B a circle BHF with radius equal to the side of SOLUTIONS OF SENATE-HOUSE ...
... GE is twice the differ- ence between the two sides BE , ED . Whence the following construction . Take GE = half the given difference , describe B a circle BHF with radius equal to the side of SOLUTIONS OF SENATE-HOUSE ...
Side 2
With Solutions Henry William Watson, Edward John Routh. a circle BHF with radius equal to the side of the given square , and cutting GE produced in B and F. Then BE , EF are the sides of the rectangle required . 3. If two chords AB , AC ...
With Solutions Henry William Watson, Edward John Routh. a circle BHF with radius equal to the side of the given square , and cutting GE produced in B and F. Then BE , EF are the sides of the rectangle required . 3. If two chords AB , AC ...
Side 7
... radius of nearly three miles ; the length of the carriage being seven feet and the breadth of the partition four inches . Owing to the great distance of the star , the motion of the carriage parallel to itself has no effect upon the ...
... radius of nearly three miles ; the length of the carriage being seven feet and the breadth of the partition four inches . Owing to the great distance of the star , the motion of the carriage parallel to itself has no effect upon the ...
Side 8
... radius of the circumscribing circle is the same for both triangles . See fig . 3 . 1 = - b 2 sin B ' and this The centres of the circles O ' and O are situated in the line ODO ' , which bisects BC at right angles , and since the per ...
... radius of the circumscribing circle is the same for both triangles . See fig . 3 . 1 = - b 2 sin B ' and this The centres of the circles O ' and O are situated in the line ODO ' , which bisects BC at right angles , and since the per ...
Side 12
... radius of the ring , angle HOB , μ the coefficient of friction , W the weight of the rod , and R the normal action at C. We may replace W acting at G by W ( r - a ) at O and wa ↑ α at C , and this latter by W - cos a , perpendicular to ...
... radius of the ring , angle HOB , μ the coefficient of friction , W the weight of the rod , and R the normal action at C. We may replace W acting at G by W ( r - a ) at O and wa ↑ α at C , and this latter by W - cos a , perpendicular to ...
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Cambridge Senate-house Problems and Riders for the Year 1860: With Solutions Henry William Watson,Edward John Routh Uten tilgangsbegrensning - 1860 |
Cambridge Senate-house Problems and Riders for the Year 1860: With Solutions Henry William Watson,Edward John Routh Uten tilgangsbegrensning - 1860 |
Cambridge Senate-house Problems and Riders for the Year 1860: With Solutions Henry William Watson,Edward John Routh Uten tilgangsbegrensning - 1860 |
Vanlige uttrykk og setninger
acceleration angular velocity Arabic numbers asymptotes attraction axes axis bisects Cambridge centre of force centre of gravity chord circle circular cloth co-ordinates cone conic conic section constant cos² Crown 8vo curvature cylinder described diameter differential equation direction directrix distance drawn dt dt ellipse ellipsoid equal angles equiangular spiral equilibrium extremity Fcap fixed point fluid foci focus given point Hence horizontal hyperbola inclined intersection latus rectum length locus MACMILLAN & CO.'S meridian motion normal parabola parallel particle perpendicular point of contact position pressure prove ratio respectively right angles Roman numbers SENIOR MODERATOR shew sides sin² singular solution smooth sphere spherical straight line string subtend surface tangent tension triangle Trinity College uniform vertex vertical Vis Viva weight аф
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