 | Charles Hutton - 1807 - 464 sider
...of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece of timber, whose bases are squares, each...inches ; also, the length or perpendicular altitude 2-1 feet. Ans. 19.£. Ex. 2. Required the content of a pentagonal frustum, •whose height is 5 feet,... | |
 | Charles Hutton - 1811 - 494 sider
...of the product^ to multiply by the length, for the content. EX. 1 . To find the number of solid feet in a piece of timber, whose bases are squares, each...side of the less end 6 inches ; also, the length or the perpendicular altitude 24 feet. Ans. 19-£-. EX. 2. Required the content of a pentagonal frustum,whose... | |
 | Charles Hutton - 1812 - 620 sider
...of solid feet in a piece of timber, whose bases arc squares, each side of the greater end being 1 5 inches, and each side of the less end 6 inches ; also, the length or perpendicular altitude 24 feet. Ans. 19^. Ex. 2. Required the content of a pentagonal frustum, whose height is 5 feet, each... | |
 | Charles Hutton - 1816 - 610 sider
...of the product to multiply 1)) the length, for the content. Ex 1. To find the number of solid feet in a piece of timber, whose bases are squares, each...15 inches, and each side of the less end 6 inches ; afso, the Jength or perpendicular altitude 24 fee{. . Ans. 19J. Ex. 2. Required the content of a... | |
 | Charles Hutton - 1818 - 646 sider
...of the product to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece of timber, whose bases are squares, each side of the greater end being 16 inches, and each side of the less end 6 inches ; also, the length or perpendicular altitude 24 feet.... | |
 | Charles Hutton - 1822 - 616 sider
...the content. E*. 1. To find the nnmber of solid feet in a piece of timfcer. whose bases are- square*, each side of the greater end being 15 inches, and...inches ; also, the length or perpendicular altitude 24 feet. Ans. U'! Ex. 2. Required the content of a pentagonal frustum, whose height is 6 leet, each... | |
 | Charles Hutton - 1831 - 660 sider
...of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece of timber, whose bases are squares, each...side of the less end 6 inches ; also, the length or the perpendicular altitude 24 feet. Ans. 19^. Ex. 2. Required the content of a pentagonal frustum,... | |
 | Adrien Marie Legendre - 1836 - 394 sider
...the sum by one-third of the altitude (Book VII. Prop. XVI1I.). 1. To find the number of solid feet in a piece of timber, •whose bases are squares, each side of the lower base being 15 inches, and each side of the upper base 6 inches, the altitude being 24 feet. Ans.... | |
 | George Willson - 1836 - 202 sider
...found by the rule before laid down. 13. What number of solid feet iii a piece of timber, whose ends are squares, each side of the greater end being -15 inches, and of the less end 6 inches, and the length or perpendicular altitude 24 feet? Ans. 19^ feet. 14. How... | |
 | Frederick Augustus Griffiths - 1840 - 436 sider
...area of the base, to the mean proportional required. Example. — Required the number of solid feet in a piece of Timber, whose bases are squares, each side of the greater end being 1 5 inches, and each side of the less end 6 inches ; also the length of the perpendicular altitude... | |
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... 07958 in using the circumferences ; then taking one-third of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece of timber, whose bases are squares, each side of the greater end being 15 inches,... 
