 From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area.  Explanatory Mensuration - Side 31av Alfred Hiley - 1879 - 188 siderUten tilgangsbegrensning - Om denne boken
 | Samuel Webber - 1808 - 466 sider
...sicks only arc given ; — add the three sides together, and take half the sum ; from the halt. sum subtract each side separately ; multiply the half sum and the three remainders continually together ; and the square root of the last product will be the area of the triangle. •... | |
 | Thomas Keith - 1810 - 478 sider
...these four logarithms, is the logarithmical sine of half the angle sought. (H. 215.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmica! co-secants of half the sum of the sides, and of the difference... | |
 | Andrew Mackay - 1811 - 162 sider
...easily measured by the above method. In this case, therefore, the three sides are to be measured. Now from half the sum of the th'ree sides, subtract each side separately; then extract the square root of the product of half the sum of the sides by the three differences ;... | |
 | John Nicholson - 1825 - 838 sider
...three sides only are given : Add the three sides together, and take half the sum ; from the half sum subtract each side separately ; multiply the half sum and the three remainders continually together ; and the square root of the last product will be the area of the triangle. Ex.... | |
 | Thomas Keith - 1826 - 504 sider
...these four logarithms, is the logarithmical sine of half the angle sought. (F. 184.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmical co-secants of half the sum of the sides, and of the difference... | |
 | Zadock Thompson - 1826 - 176 sider
...— If the three sides only are given, add these together, and tuke half the sum ; from the half sum subtract each side separately ; multiply the half sum and the three remainders continually together, and the square root of the last product will be the area of the triangle. Examples.... | |
 | John Gummere - 1828 - 404 sider
...adjacent angles 37° 30' and.48°15'? Ans. 6 A. 3R. 18 P. PROBLEM V. To find the. area of a triangle when the three sides are given. From half the sum of the three sides subtract each side severally; multiply the half sum and the three remainders continually together, and the square root... | |
 | Dudley Leavitt - 1830 - 154 sider
...the three sides of a triangle are given, the area may be found thus, without a perpendicular. Erom half the sum of the three sides, subtract each side separately ; multiply the half sum and 3 remainders continually together, and the square root of the last product will be the area. Therefore,... | |
 | John Nicholson (Civil engineer) - 1830 - 240 sider
...three sides only are given : Add the three sides together, and take half the sum ; from the half sum subtract each side separately ; multiply the half sum and the three remainders continually together ; and the square root of the last product will be the area of the triangle. Ex.... | |
 | Ira Wanzer - 1831 - 408 sider
...in Problem III. 2. When the three sides of the triangle are given, the area may be found as follows: From half the sum of the three sides subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root... | |
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