 | Thomas Perronet Thompson - 1833 - 168 sider
...PROPOSITION XLVIII. THEOREM. — If the square described on one of the sides of a triangle, be equal to the sum of the squares described on the other two sides of it; the angle made by those two sides is a right angle. Let ABC be a triangle, which is such that... | |
 | Charles Davies - 1840 - 262 sider
...4=90 degrees. 10. In every right angled triangle, the square described on the hypothenuse, is equal to the sum of the squares described on the other two sides. Thus, if ABC be a right angled triangle, right angled at C, then will the square D described on AB... | |
 | Scotland free church, gen. assembly - 1847 - 554 sider
...makes the alternate angles equal. 2. If the square described on one of the sides of a triangle be equal to the sum of the squares described on the other two sides, these sides contain a right angle. 3. Divide a given line into two parts, so that the rectangle contained... | |
 | Nicholas Tillinghast - 1844 - 108 sider
...Problem IV.) PROP. VII. THEOREM. The square described on the hypotenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides. Let the triangle be KDI, right angled at I. Describe squares onKD, KI, DI ; then we have to prove that... | |
 | James Bates Thomson - 1844 - 268 sider
...words, BC^AB'-f-AC". Therefore, The square described on the hypolhcnuse of a right-angled triangle, is equivalent to the sum of the squares described on the other two sides. Cor. 1. Hence, by transposition, the square of one of the sides of a right-angled triangle is equivalent... | |
 | Charles Davies - 1846 - 254 sider
...triangle equal to ? In every right-angled triangle, the square described on the hypothenuse, is equal to the sum of the squares described on the other two sides. Thus, if ABC be a rightangled triangle, right-angled at C, then will the square D, described on AB,... | |
 | James Bates Thomson - 1846 - 354 sider
...principle in geometry, that the square described on the hypothenuse of a right-angled triangle, is equal to the sum of the squares described on the other two sides. (Leg. IV. 11. Euc. I. 47.) Thus if the base of the triangle ABC is 4 feet, and the perpendicular 3... | |
 | James Bates Thomson - 1847 - 426 sider
...30. 34967ft-. 371 578. The square described on the hypothenuse of a rightangled triangle, is equal to the sum of the squares described on the other two sides. (Thomson's Legendre, B. IV. 11, Euc. I. 47.) The truth of this principle may be seen from the following... | |
 | James Bates Thomson - 1847 - 432 sider
...contains 25 sq. ft. Hence, the square described on the hi/pothenuse of any right-angled triangle, is equal to the sum of the squares described on the other two sides. DBS. Since the square of the hypothenuse BC, is 25, it follows that the , or 5, must be the hypothenuse... | |
 | James Bates Thomson - 1848 - 434 sider
...575-580.] SQUARE ROOT. 371 578. The square described on the hypothenuse of a rightangled triangle, is equal to the sum of the squares described on the other two sides. (Thomson's Legendre, B. IV. 11, Euc. I. 47.) The truth of this principle may be seen from the following... | |
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The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides. 
