Mensuration for beginners [With] Answers1883 |
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Resultat 6-10 av 21
Side 108
... diameter and 1 in . thick ; find its cost , at 1s . per c . ft . ( 13 ) The expense of excavating a round well , of ... base are given . RULE . Divide the volume by the area of its base , and the quotient will give the height . Ex . 1 ...
... diameter and 1 in . thick ; find its cost , at 1s . per c . ft . ( 13 ) The expense of excavating a round well , of ... base are given . RULE . Divide the volume by the area of its base , and the quotient will give the height . Ex . 1 ...
Side 110
... diameter of the base of a right cylinder is 14 in . , and the height is 10 in .; find the area of the convex surface , and of the whole surface . Circumference of base = 22 × 14 = 44 in . ( Art . 99. ) Area of convex surface = 44 × 10 ...
... diameter of the base of a right cylinder is 14 in . , and the height is 10 in .; find the area of the convex surface , and of the whole surface . Circumference of base = 22 × 14 = 44 in . ( Art . 99. ) Area of convex surface = 44 × 10 ...
Side 117
... base 5 ft .; find the cost of tooling the side faces , at 1s . 6d . per sq . ft . ( 14 ) The base of a pyramid is a regular octagon , each side being 18 ft . , and each of the other edges of ... diameter of the base of a THE RIGHT CONE . 117.
... base 5 ft .; find the cost of tooling the side faces , at 1s . 6d . per sq . ft . ( 14 ) The base of a pyramid is a regular octagon , each side being 18 ft . , and each of the other edges of ... diameter of the base of a THE RIGHT CONE . 117.
Side 117
William Dodds. Ex . 1. The diameter of the base of a right cone is 28 in . , and the perpendicular height 15 in .; required the volume . Area of base = 14 × 28 × 28 = 616 sq . in . ( Art . 102. ) Volume of cone = × 616 × 15 = 3080 c . in ...
William Dodds. Ex . 1. The diameter of the base of a right cone is 28 in . , and the perpendicular height 15 in .; required the volume . Area of base = 14 × 28 × 28 = 616 sq . in . ( Art . 102. ) Volume of cone = × 616 × 15 = 3080 c . in ...
Side 117
... circumference of the base of the cone being the arc of the sector , and the slant height of the cone the radius of the sector . Now the area of a sector is found by multiplying half the arc by the radius ( Art . 119 ) ; hence the area ...
... circumference of the base of the cone being the arc of the sector , and the slant height of the cone the radius of the sector . Now the area of a sector is found by multiplying half the arc by the radius ( Art . 119 ) ; hence the area ...
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Vanlige uttrykk og setninger
9 ft A B C D ABCD acres angle subtended Area of base broad centre circle circular circum Circumference of base contains cube cubic foot curved surface cwts cylinder depth diagonal diam Diameter of base equal equilateral triangle find the area Find the cost find the expense find the height find the length find the number Find the side find the volume following dimensions found by Art heptagon hexagon hypotenuse length of carpet Multiply number of cubic number of degrees papering a room parallel sides parallelopiped paving perimeter perpendicular distance perpendicular height polygon prism quotient Radius of base rectangle regular polygon Required the area rhomboid rhombus right cone right-angled triangle round RULE sector slant height solid content square chains square feet square field square links square pyramid square root square yard thick trapezium trapezoid triangular field whole surface width
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 52 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 52 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 41 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 45 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 103 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 101 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 105 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.