The First Six Books: Together with the Eleventh and TwelfthJ. Balfour, 1781 - 520 sider |
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Side 74
... circumference equal to FG : For , if there can , let it be FK ; and becaufe FK is equal to FG , and FG to FH , FK is ... circumference , where- of one paffes through the centre ; of those which fall upon the concave circumference , the ...
... circumference equal to FG : For , if there can , let it be FK ; and becaufe FK is equal to FG , and FG to FH , FK is ... circumference , where- of one paffes through the centre ; of those which fall upon the concave circumference , the ...
Side 75
... circumference , one upon each fide of the leaft : At the point M , in the ftraight line MD , make the angle DMB equal to the angle DMK , and join DB : And becaufe MK is equal to MB , and MD common to the triangles KMD , BMD , the two ...
... circumference , one upon each fide of the leaft : At the point M , in the ftraight line MD , make the angle DMB equal to the angle DMK , and join DB : And becaufe MK is equal to MB , and MD common to the triangles KMD , BMD , the two ...
Side 76
... circumference there fall more than two equal ftraight lines , viz . DA , DB , DC , the point D is the centre of the circle . DE For , if not , let E be the centre , join DE and produce it to the cir cumference in F , G ; then FG is a ...
... circumference there fall more than two equal ftraight lines , viz . DA , DB , DC , the point D is the centre of the circle . DE For , if not , let E be the centre , join DE and produce it to the cir cumference in F , G ; then FG is a ...
Side 77
... circumference of a circle cannot cut another in more than two points . Q.E. D. PROP . XI . THEOR . I two circles touch each other internally , the ftraight line which joins their centres being produced fhall pafs through the point of ...
... circumference of a circle cannot cut another in more than two points . Q.E. D. PROP . XI . THEOR . I two circles touch each other internally , the ftraight line which joins their centres being produced fhall pafs through the point of ...
Side 79
... circumference of the circle ACK , the ftraight line AC which joins them fhall fall within the circle ACK : And the circle ACK is without the cir- cle ABC ; and therefore the ftraight line AC is without this laft circle ; but , be- cause ...
... circumference of the circle ACK , the ftraight line AC which joins them fhall fall within the circle ACK : And the circle ACK is without the cir- cle ABC ; and therefore the ftraight line AC is without this laft circle ; but , be- cause ...
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The First Six Books: Together with the Eleventh and Twelfth Euclid Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio bifected Book XI cafe centre circle ABCD circumference cone confequently cylinder defcribed demonftrated drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fide BC fides fimilar firft firſt folid angle fome fore fphere fquare of AC ftraight line AB ftraight line BC given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs likewife oppofite parallel parallelepipeds parallelogram perpendicular plane angles prifms PROP propofition pyramid ratio of BC rectangle contained rectilineal figure right angles ſquare thefe THEOR theſe triangle ABC wherefore
Populære avsnitt
Side 472 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Side 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Side 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.
Side 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.
Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...
Side 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.