Elementary and practical Arithmetic on the inductive system, by analysis and synthesis, etcWaterhouse & Company, 1844 - 12 sider |
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Side 163
... diameters . 45. A cylinderoid is a solid similar to the frustum of a cone , one base may be an ellipsis , and the other a disproportional ellipsis or circle . " 46. A prismoid is a solid similar to the frustum of a pyramid ; but its ...
... diameters . 45. A cylinderoid is a solid similar to the frustum of a cone , one base may be an ellipsis , and the other a disproportional ellipsis or circle . " 46. A prismoid is a solid similar to the frustum of a pyramid ; but its ...
Side 164
... diameter . 19. The chord of an arc of 60 degrees , is equal in length to the radius of the circle of which the arc is a part . 20. The sines on the same diameter increase in length till becoming radius , decreasing after . Hence radius ...
... diameter . 19. The chord of an arc of 60 degrees , is equal in length to the radius of the circle of which the arc is a part . 20. The sines on the same diameter increase in length till becoming radius , decreasing after . Hence radius ...
Side 165
... diameter and circumference ; and the product of the circumference and the height of its segment is the area of that segment . 37. The capacity of solids is as the cubes of their properties . NOTE . For other definitions , or principles ...
... diameter and circumference ; and the product of the circumference and the height of its segment is the area of that segment . 37. The capacity of solids is as the cubes of their properties . NOTE . For other definitions , or principles ...
Side 169
... diameters being given . RULE . - Multiply the product of the two diameters by .7854 , the result is the area . * Meridian , ( L. meridies ) mid day . Meridian , a north and south line . Reason . The area of a circle is only .7854 18 ...
... diameters being given . RULE . - Multiply the product of the two diameters by .7854 , the result is the area . * Meridian , ( L. meridies ) mid day . Meridian , a north and south line . Reason . The area of a circle is only .7854 18 ...
Side 170
... diameter , which is obvious . Also , see Sundry Tables . 13. Given , the versed sine of an arc and the diameter of a circle , to find the chord . RULE . From the diameter subtract the versed sine ; multiply the remainder by the versed ...
... diameter , which is obvious . Also , see Sundry Tables . 13. Given , the versed sine of an arc and the diameter of a circle , to find the chord . RULE . From the diameter subtract the versed sine ; multiply the remainder by the versed ...
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Elementary and practical Arithmetic on the inductive system, by analysis and ... Charles WATERHOUSE Uten tilgangsbegrensning - 1844 |
Elementary and Practical Arithmetic on the Inductive System, by Analysis and ... Charles Waterhouse Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
acres amount angle annexed annuity arithmetical bought breadth cask cent CHARLES WATERHOUSE chord ciphers circle column compound compound interest contained cost cube root cubic decimal denominator diameter difference distance divide dividend division divisor dollars Dominical letter earth equal EXAMPLES feet fraction frustum gain gallons geometrical series Give given number half Hence hour hypotenuse improper fraction inches interest Lastly least common multiple left hand length less measure method miles minuend mixed number months multiplicand multiplied NOTE number of terms operation paid perpendicular piece pound preceding rule present worth principle proceed proportion quantity questions Questions-What quotient ratio Reduce remainder repetend right hand rods RULE.-Divide RULE.-Multiply share side signifies sold solid specific gravity square root subtract subtrahend Suppose surface third triangle units vulgar fraction weight whole numbers yards yearly
Populære avsnitt
Side 36 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Side 37 - Multiply all the numerators together for a new numerator, and all the denominators together for a new denominator.
Side 154 - Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Side 192 - The pulley is a small wheel, movable about its axis by means of a cord, which passes over it. When the axis of a pulley is fixed, the pulley only changes the direction of the power ; if movable pulleys are used, an equilibrium is produced, when the power is to the weight, as one to the number of ropes applied to them.
Side 137 - Take a series of as many terms, decreasing by 1, from the given number, out of which the election is to be made, and find the product of all the terms.
Side 77 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Side 69 - Having the sum of two numbers and the difference of their squares* given, to find those numbers. Rule. Divide the difference of their squares by the sum of the numbers, and the quotient will be their difference : You will then have their sum and difference, to find the numbers by Problem 4.
Side 29 - There is a certain number which being divided by 7, the quotient resulting multiplied by 3, that product divided by 5, from the quotient 20 being subtracted, and 30 added to the remainder, the half sum shall make 65 ; can yon teli jnethe number?
Side 57 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Side 96 - A man bought apples at 5 cents a dozen, half of which he exchanged for pears, at the rate of 8 apples for 5 pears; he then sold all his apples and pears at a cent apiece, and thus gained 19 cents. How many apples did he buy, and how much did they cost ? 122.