The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry, from the Edition of Dr. Robert Simson ... With ExercisesCharles Henry Law, 1854 - 120 sider |
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Resultat 6-10 av 24
Side 45
... double of the triangle FBC , because these also are upon the same base FB , and between the same parallels FB , GC . But the doubles of equals are equal ( Ax . 6. ) to one another ; therefore 7. The parallelogram BL is equal to the ...
... double of the triangle FBC , because these also are upon the same base FB , and between the same parallels FB , GC . But the doubles of equals are equal ( Ax . 6. ) to one another ; therefore 7. The parallelogram BL is equal to the ...
Side 53
... double of AK ; but AK , CE , are the gnomon AKF , together with the square CK ; there- fore but 3 . The gnomon AKF , together with the square CK , is double of AK ; 4. Twice the rectangle AB , BC , is double of AK , for BK is equal ( II ...
... double of AK ; but AK , CE , are the gnomon AKF , together with the square CK ; there- fore but 3 . The gnomon AKF , together with the square CK , is double of AK ; 4. Twice the rectangle AB , BC , is double of AK , for BK is equal ( II ...
Side 55
... double of the square of half the line , and of the square of the line between the points of section . Let the straight line AB be divided at the point Cinto two equal , and at D into two unequal parts ; the squares of AD , DB , are ...
... double of the square of half the line , and of the square of the line between the points of section . Let the straight line AB be divided at the point Cinto two equal , and at D into two unequal parts ; the squares of AD , DB , are ...
Side 56
... double sq . of AC . A 56 с D [ 29 of 4. 39. Kat double СД 29 A = double 293.0 % ) 4C , CD B EUCLID'S ELEMENTS . From the point C draw ( I. 11. ) CE at right angles to AB , and make it equal ( I. 3. ) to AC or CB , and join EA , EB ...
... double sq . of AC . A 56 с D [ 29 of 4. 39. Kat double СД 29 A = double 293.0 % ) 4C , CD B EUCLID'S ELEMENTS . From the point C draw ( I. 11. ) CE at right angles to AB , and make it equal ( I. 3. ) to AC or CB , and join EA , EB ...
Side 57
... double of the squares of AC , CD ; and DF is equal to DB ; therefore 16 . AC , CD . The squares of AD , DB , are double of the squares of Therefore , if a straight line , & c . Q E.D. PROP . X. - THEOREM . If a straight line be ...
... double of the squares of AC , CD ; and DF is equal to DB ; therefore 16 . AC , CD . The squares of AD , DB , are double of the squares of Therefore , if a straight line , & c . Q E.D. PROP . X. - THEOREM . If a straight line be ...
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The Synoptical Euclid; Being the First Four Books of Euclid's Elements of ... Euclid,Samuel A. GOOD Uten tilgangsbegrensning - 1854 |
The synoptical Euclid; being the first four books of Euclid's Elements of ... Euclides Uten tilgangsbegrensning - 1853 |
Vanlige uttrykk og setninger
AB is equal AC is equal adjacent angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angle equal base BC bisected circle ABC circumference diameter double draw equal angles equal Constr equal Hyp equal straight lines equal to BC equilateral and equiangular EUCLID'S ELEMENTS exterior angle given circle given point given rectilineal angle given straight line given triangle gnomon greater inscribed interior and opposite less Let ABC Let the straight likewise opposite angles parallel to CD parallelogram pentagon perpendicular point F produced Q.E.D. PROP rectangle AE rectangle contained remaining angle required to describe right angles semicircle side BC square of AC straight line AB straight line AC straight line drawn touches the circle triangle ABC twice the rectangle