## Trigonometry, Plane and Spherical: With the Construction and Application of Logarithms |

### Inni boken

Resultat 6-10 av 16

Side 55

... of D their Sum , in the first Case , and the Tangent of their Difference , in the

second , and let CF , perpendicular to the Radius DN , be

of the equiangular Triangles BAD and BFC , we shall have BD X CF = DA BC 7 3

.

... of D their Sum , in the first Case , and the Tangent of their Difference , in the

second , and let CF , perpendicular to the Radius DN , be

**drawn**: Then , becauseof the equiangular Triangles BAD and BFC , we shall have BD X CF = DA BC 7 3

.

Side 58

In AC , produced , take CD = BC , and let BD be

) it will be , AD + AB : AD- AB :: Tang . ABD + D 180 ° A 2 B = 90 ° { A ) : Tang .

ABD - D ABD CBD A ( ABD 2 . 2 ABC that is , AC + BC + AB : AC + BC - AB :: Co ...

In AC , produced , take CD = BC , and let BD be

**drawn**: Then ( by Tbeor . 5 . p . 6.) it will be , AD + AB : AD- AB :: Tang . ABD + D 180 ° A 2 B = 90 ° { A ) : Tang .

ABD - D ABD CBD A ( ABD 2 . 2 ABC that is , AC + BC + AB : AC + BC - AB :: Co ...

Side 60

с D In the greater Side CA let there be taken CDCB , and let BD be

likewise CE , perpendicular to BD . It is A B manifest , because CD = CB , that

CDB and CBD are equal to one another , and that each of them is also equal to

half ...

с D In the greater Side CA let there be taken CDCB , and let BD be

**drawn**, andlikewise CE , perpendicular to BD . It is A B manifest , because CD = CB , that

CDB and CBD are equal to one another , and that each of them is also equal to

half ...

Side 61

D с F Let ABCD be a Circle described about the Triangle , and from O , the

Center thereof , let OB and OC be

meeting the Periphery in D , and EOF , perpendicular to AB , meeting DC iņ F.

Then it ...

D с F Let ABCD be a Circle described about the Triangle , and from O , the

Center thereof , let OB and OC be

**drawn**; moreover ,**draw**CD parallel to B A , Bmeeting the Periphery in D , and EOF , perpendicular to AB , meeting DC iņ F.

Then it ...

Side 62

... so is the Difference of these two , to the perpendicular Height of the Triangle . с

Let a Circle be described about the Triangle and from O , the Center thereof , let

OA , OC and OD be

... so is the Difference of these two , to the perpendicular Height of the Triangle . с

Let a Circle be described about the Triangle and from O , the Center thereof , let

OA , OC and OD be

**drawn**; also let CF , parallel to AB , be**drawn**, meeting DO ...### Hva folk mener - Skriv en omtale

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### Andre utgaver - Vis alle

Trigonometry: Plane and Spherical; with the Construction and Application of ... Thomas Simpson Uten tilgangsbegrensning - 1799 |

Trigonometry, Plane and Spherical;: With the Construction and Application of ... Thomas Simpson Uten tilgangsbegrensning - 1765 |

Trigonometry, Plane and Spherical: With the Construction and Application of ... Thomas Simpson Uten tilgangsbegrensning - 1799 |

### Vanlige uttrykk og setninger

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### Populære avsnitt

Side 1 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees; and each degree into 60 minutes, each minute into 60 seconds, and so on.

Side 3 - Canon, is a table showing the length of the sine, tangent, and secant, to every degree and minute of the quadrant, with respect to the radius, which is expressed by unity or 1, with any number of ciphers.

Side 6 - In every plane triangle, it will be, as the sum of any two sides is to their difference...

Side 41 - The sum of the logarithms of any two numbers is equal to the logarithm of their product. Therefore, the addition of logarithms corresponds to the multiplication of their numbers.

Side 13 - If the sine of the mean of three equidifferent arcs' dius being unity) be multiplied into twice the cosine of the common difference, and the sine of either extreme be deducted from the product, the remainder will be the sine of the other extreme. (B.) The sine of any arc above 60°, is equal to the sine of another arc as much below 60°, together with the sine of its excess above 60°. Remark. From this latter proposition, the sines below 60° being known, those of arcs above 60° are determinable...

Side 31 - ... is the tangent of half the vertical angle to the tangent of the angle which the perpendicular CD makes with the line CF, bisecting the vertical angle.

Side 73 - BD, is to their Difference ; fo is the Tangent of half the Sum of the Angles BDC and BCD, to the Tangent of half their Difference.

Side 28 - As the sum of the sines of two unequal arches is to their difference, so is the tangent of half the sum of those arches to the tangent of half their difference : and as the sum...

Side 68 - In any right lined triangle, having two unequal sides ; as the less of those sides is to the greater, so is radius to the tangent of an angle ; and as radius is to the tangent of the excess of...