The Elements of Euclid; viz. the first six books, together with the eleventh and twelfth. Also the book of Euclid's Data. By R. Simson. To which is added, A treatise on the construction of the trigonometrical canon [by J. Christison] and A concise account of logarithms [by A. Robertson].1834 |
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Resultat 6-10 av 82
Side 92
... equal to the square of AC † , and that AC is equal to BD , the rectangle AB , BC is equal to the square of BD : and because from the ... equiangular pentagon in the circle ABCDE . * F B E * 2.4 .. Describe an isosceles 92 EUCLID'S ELEMENTS .
... equal to the square of AC † , and that AC is equal to BD , the rectangle AB , BC is equal to the square of BD : and because from the ... equiangular pentagon in the circle ABCDE . * F B E * 2.4 .. Describe an isosceles 92 EUCLID'S ELEMENTS .
Side 93
... equiangular to the triangle FGH , so that the angle CAD may be equal to the angle at F , and each of the angles ACD ... equiangular ; for , because the circumference AB is equal to the circumference DE , if to each be added BCD , the ...
... equiangular to the triangle FGH , so that the angle CAD may be equal to the angle at F , and each of the angles ACD ... equiangular ; for , because the circumference AB is equal to the circumference DE , if to each be added BCD , the ...
Side 95
... equal † to KL : in like + 6 Ax . manner it may be shewn , that GH , GM , ML are each of them equal to HK , or KL ; therefore the pentagon GHKLM is equilateral . It is also equiangular ; for , since the angle FKC is equal to the angle ...
... equal † to KL : in like + 6 Ax . manner it may be shewn , that GH , GM , ML are each of them equal to HK , or KL ; therefore the pentagon GHKLM is equilateral . It is also equiangular ; for , since the angle FKC is equal to the angle ...
Side 96
... equilateral and equiangular pentagon . Let ABCDE be the given equilateral and equiangular pen- tagon ; it is required to describe a circle about it . # B E Bisect the angles BCD , CDE by the straight lines CF , FD , and from the point F ...
... equilateral and equiangular pentagon . Let ABCDE be the given equilateral and equiangular pen- tagon ; it is required to describe a circle about it . # B E Bisect the angles BCD , CDE by the straight lines CF , FD , and from the point F ...
Side 97
... equiangular pentagon ABCDE . Which was to be done . PROPOSITION XV . PROB . - To inscribe an equilateral and equiangular hexagon See N. in a given circle . Let ABCDEF be the given circle ; it is required to inscribe an equilateral and ...
... equiangular pentagon ABCDE . Which was to be done . PROPOSITION XV . PROB . - To inscribe an equilateral and equiangular hexagon See N. in a given circle . Let ABCDEF be the given circle ; it is required to inscribe an equilateral and ...
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The Elements of Euclid; viz. the first six books, together with the eleventh ... Euclides Uten tilgangsbegrensning - 1814 |
Vanlige uttrykk og setninger
ABC is given AC is equal altitude angle ABC angle BAC base BC bisected centre circle ABCD circle EFGH circumference common logarithm cone Constr cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid ex æquali excess fore given angle given in magnitude given in position given in species given magnitude given ratio given straight line gnomon greater join less Let ABC logarithm multiple parallel parallelogram perpendicular point F polygon prism Prop proportionals Q. E. D. PROPOSITION radius ratio of AE rectangle CB rectangle contained rectilineal figure remaining angle right angles segment shewn sides BA similar sine solid angle solid parallelopiped square of AC straight line AB straight line BC tangent THEOR.-If tiple triangle ABC vertex wherefore
Populære avsnitt
Side 32 - To a given straight line, to apply a parallelogram which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle...
Side 138 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 39 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 22 - If a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another...
Side 41 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together •with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced.
Side 5 - If two triangles have two sides of the one equal to two sides of the other, each to each, but the...
Side 38 - IF a straight line be divided into any two parts, the rectangles contained by the whole and each of the parts, are together equal to the square of the whole line. Let the straight line AB be divided...
Side 262 - Again ; the mathematical postulate, that " things which are equal to the same are equal to one another," is similar to the form of the syllogism in logic, which unites things agreeing in the middle term.
Side 89 - PBOR. —To describe an isosceles triangle, having each of the angles at the base, double of the third angle. Take any straight...
Side 165 - Wherefore, in equal circles &c. QED PROPOSITION B. THEOREM If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.