Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement of the Quadrature of the Circle and the Geometry of SolidsF. Nichols, 1806 - 311 sider |
Inni boken
Resultat 6-10 av 30
Side 57
... half " that line . " Otherwise . • " AD2 = AC2 + CD2 + 2CD.AC3 , and CD2 = CB + BD2 + a4 2 . 2CB.BD. But CD = 2CB , therefore CD2-4CB2 , and also 2CD.AC = 4CB.AC ; therefore AD2 = AC2 + 4BC2 + 4BC.AC . Now BCBC.ACAB.BC ; therefore AD2 ...
... half " that line . " Otherwise . • " AD2 = AC2 + CD2 + 2CD.AC3 , and CD2 = CB + BD2 + a4 2 . 2CB.BD. But CD = 2CB , therefore CD2-4CB2 , and also 2CD.AC = 4CB.AC ; therefore AD2 = AC2 + 4BC2 + 4BC.AC . Now BCBC.ACAB.BC ; therefore AD2 ...
Side 58
... half the line , and of the square of the line between the points of section . Let the straight line AB be divided at ... half C D B of a right angle . For the same reason each of the angles CEB , EBC is half a right an- gle . Hence the ...
... half the line , and of the square of the line between the points of section . Let the straight line AB be divided at ... half C D B of a right angle . For the same reason each of the angles CEB , EBC is half a right an- gle . Hence the ...
Side 59
... half the line bisected , and of the square of the line made up of the half and the part produced . Let the straight line AB be bisected in C , and produced to the point D ; the squares of AD , DB are double of the squares of AC , CD ...
... half the line bisected , and of the square of the line made up of the half and the part produced . Let the straight line AB be bisected in C , and produced to the point D ; the squares of AD , DB are double of the squares of AC , CD ...
Side 60
... half a right angle . Hence AEB is a right angle . Because EBC is half a right angle , DBG is also half a right angle . But BDG is a a right angle , because it is equal to the alternate angle DCE ; therefore the remaining angle DGB is ...
... half a right angle . Hence AEB is a right angle . Because EBC is half a right angle , DBG is also half a right angle . But BDG is a a right angle , because it is equal to the alternate angle DCE ; therefore the remaining angle DGB is ...
Side 65
... half the side bisected , and of the square of the line drawn from the point of bisection to the op- posite angle of the triangle . Let ABC be a triangle , of which the side BC is bisected in D , and DA drawn to the opposite angle ; the ...
... half the side bisected , and of the square of the line drawn from the point of bisection to the op- posite angle of the triangle . Let ABC be a triangle , of which the side BC is bisected in D , and DA drawn to the opposite angle ; the ...
Andre utgaver - Vis alle
Elements of Geometry: Containing the First Six Books of Euclid with a ... John Playfair Uten tilgangsbegrensning - 1855 |
Elements of Geometry: Containing the First Six Books of Euclid, with a ... John Playfair Uten tilgangsbegrensning - 1847 |
Elements of Geometry: Containing the First Six Books of Euclid, with a ... John Playfair Uten tilgangsbegrensning - 1839 |
Vanlige uttrykk og setninger
ABC is equal ABCD altitude angle ABC angle ACB angle BAC angle contained angle EDF arch base BC bisected Book centre circle ABC circumference coincide cylinder definition demonstrated diameter draw drawa equal angles equiangular equilateral polygon equimultiples Euclid exterior angle fore four right angles given circle given straight line greater inscribed interior and opposite join less Let ABC Let the straight meet multiple opposite angle parallelogram perpendicular point F polygon prism PROB produced proportional proposition pyramid Q. E. D. COR Q. E. D. PROP ratio rectangle contained rectilineal figure remaining angle segment solid angle solid parallelepipeds straight line AB straight line AC Suppl THEOR third touches the circle triangle ABC triangle DEF
Populære avsnitt
Side 121 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 42 - TO a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 63 - Therefore, in obtuse-angled triangles, &c. QED PROP. XIII. THEOREM. In every triangle, the square of the side subtending either of the acute angles is less than the squares of the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall upon it from the opposite angle, and the acute angle.
Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 183 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let AC, CF be equiangular parallelograms having the angle BCD equal to the angle ECG ; the ratio of the parallelogram AC to the parallelogram CF is the same with the ratio which is compounded •f the ratios of their sides.
Side 3 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 291 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 160 - ... extremities of the base shall have the same ratio which the other sides of the triangle have to one...
Side 10 - ... shall be greater than the base of the other. Let ABC, DEF be two triangles, which have the two sides AB, AC, equal to the two DE, DF, each to each, viz.
Side 14 - Therefore, upon the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extretnity equal to one another.