A graduated course of problems in practical plane and solid geometry |
Inni boken
Resultat 6-10 av 38
Side 19
James Martin (of the Wedgwood inst, Burslem.) 3. Mark off LN equal to GK . Join ON , and from A and B , draw AP , BQ parallel to ON ( Pr . 9 ) . The divisions L , Q , N , P , are proportional to the divisions L , B , 0 , A ( Pr . 16 ) ...
James Martin (of the Wedgwood inst, Burslem.) 3. Mark off LN equal to GK . Join ON , and from A and B , draw AP , BQ parallel to ON ( Pr . 9 ) . The divisions L , Q , N , P , are proportional to the divisions L , B , 0 , A ( Pr . 16 ) ...
Side 30
... mark off the given altitude CD on the line in the point F. 2. Join FA and FB . Then FAB is the required isosceles triangle . Problem 30 . To construct an isosceles triangle on a given base AB , having a vertical angle of 90 ° . C 90 A ...
... mark off the given altitude CD on the line in the point F. 2. Join FA and FB . Then FAB is the required isosceles triangle . Problem 30 . To construct an isosceles triangle on a given base AB , having a vertical angle of 90 ° . C 90 A ...
Side 65
... Mark off , on the circumference , the divisions 2 E , EF , equal to AB . Join 2 E , EF , FB , and the pentagon is constructed on the given line AB . NOTE . - A line must always be drawn from A to the second division on the semicircle ...
... Mark off , on the circumference , the divisions 2 E , EF , equal to AB . Join 2 E , EF , FB , and the pentagon is constructed on the given line AB . NOTE . - A line must always be drawn from A to the second division on the semicircle ...
Side 69
... Mark off , on the circumference , the divisions 12 , 23 , & c . , equal to B 1. Join 12 , 23 , & c . , and a nonagon is constructed on the given line AB . Problem 76 . To construct a regular decagon on a given line AB . 1. Produce the ...
... Mark off , on the circumference , the divisions 12 , 23 , & c . , equal to B 1. Join 12 , 23 , & c . , and a nonagon is constructed on the given line AB . Problem 76 . To construct a regular decagon on a given line AB . 1. Produce the ...
Side 70
... Mark off , on the circumference , the divisions 1 2 , 23 , & c , equal to B 1. Join 1 2 , 2 3 , & c . , and a decagon is con- structed on the given line AB . Problem 77 . To construct a regular un - decagon on a given line AB . 1 ...
... Mark off , on the circumference , the divisions 1 2 , 23 , & c , equal to B 1. Join 1 2 , 2 3 , & c . , and a decagon is con- structed on the given line AB . Problem 77 . To construct a regular un - decagon on a given line AB . 1 ...
Vanlige uttrykk og setninger
altitude angles to xy Atlas axis base BC Pr Bisect the angle bound in cloth circumference cone construct a triangle cube curve cylinder decagon describe a circle describe an arc describe the arc diameter BC distance divide draw a line draw a tangent draw lines edge ellipse equal circles equal in area equilateral triangle given circle given line given point given square ABCD given straight line given triangle ABC heptagon horizontal plane hyperbola inclined inscribe intersection isosceles triangle Join line BC line CD line of bisection lines parallel Maps mean proportional meeting number of equal octahedron parallel to xy parallelogram pentagon perpendicular to xy Philips plan and elevation PLANE GEOMETRY plane of projection point F points of division prism Problem projectors pyramid radii radius rectangle rectilineal figure regular polygon represent required circle rhombus right angles semicircle SOLID GEOMETRY square pyramid trapezium vertical plane
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Side 193 - A cone is a solid figure described by the revolution of a right-angled triangle about one of the sides containing the right angle, which side remains fixed. If the fixed side be equal to the other side containing the right angle, the cone is called a right-angled cone ; if it be less than the other side, an obtuse-angled ; and if greater, an acute-angled cone. XIX. The axis of a cone is the fixed straight line about which the triangle revolves.
Side 123 - A straight line is said to be cut in extreme and mean ratio, when the whole is to the greater segment as the greater segment is to the less.