The First Six Books: Together with the Eleventh and TwelfthJ. Balfour, 1781 - 520 sider |
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Side 82
... perpendicular to FA , and let it meet the circumference in H : And because AGD is a right angle , and DAG lefs than a right angle : DA is greater than DG : But DA is equal to DH ; therefore DH is greater than DG , the less than the ...
... perpendicular to FA , and let it meet the circumference in H : And because AGD is a right angle , and DAG lefs than a right angle : DA is greater than DG : But DA is equal to DH ; therefore DH is greater than DG , the less than the ...
Side 83
... perpendicular to DE . For , if it be not , from the point F draw FBG perpendicular to DE ; and because FGC is a right angle , GCF is an acute b 17. 1 . angle ; and to the greater angle the greateft fide is oppofite : c 19. 1 . Therefore ...
... perpendicular to DE . For , if it be not , from the point F draw FBG perpendicular to DE ; and because FGC is a right angle , GCF is an acute b 17. 1 . angle ; and to the greater angle the greateft fide is oppofite : c 19. 1 . Therefore ...
Side 84
... perpendicular to DE : In the fame manner it may be fhewn , that no other is perpen- dicular to it befides FC , that is , FC is perpendicular to DE . Therefore , if a straight line , & c . Q. E. D. A D B GE @ 18 . I ' PRO P. XIX . THEOR ...
... perpendicular to DE : In the fame manner it may be fhewn , that no other is perpen- dicular to it befides FC , that is , FC is perpendicular to DE . Therefore , if a straight line , & c . Q. E. D. A D B GE @ 18 . I ' PRO P. XIX . THEOR ...
Side 99
... perpendicular to d 1. 3 . AC , and join EB , EC , ED : And because the ftraight line EF , € 12. I. which paffes through the centre , cuts the ftraight line AC , which does not pass through the centre , at right angles , it fhall ...
... perpendicular to d 1. 3 . AC , and join EB , EC , ED : And because the ftraight line EF , € 12. I. which paffes through the centre , cuts the ftraight line AC , which does not pass through the centre , at right angles , it fhall ...
Side 112
... perpendicular to KL ; therefore each of the angles at C is a right angle : For the same reason , the angles at the points B , D are right angles : And because FCK is a right angle , the fquare of FK is equal to the fquares of FC , CK ...
... perpendicular to KL ; therefore each of the angles at C is a right angle : For the same reason , the angles at the points B , D are right angles : And because FCK is a right angle , the fquare of FK is equal to the fquares of FC , CK ...
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The First Six Books: Together with the Eleventh and Twelfth Euclid Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio bifected Book XI cafe centre circle ABCD circumference cone confequently cylinder defcribed demonftrated drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fide BC fides fimilar firft firſt folid angle fome fore fphere fquare of AC ftraight line AB ftraight line BC given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs likewife oppofite parallel parallelepipeds parallelogram perpendicular plane angles prifms PROP propofition pyramid ratio of BC rectangle contained rectilineal figure right angles ſquare thefe THEOR theſe triangle ABC wherefore
Populære avsnitt
Side 472 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Side 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Side 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.
Side 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.
Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...
Side 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.