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Side 26
... Produce AP to meet BC in Q. Because any two sides of a triangle are together greater than the third side , ( Th . 12. ) therefore AC and CQ are greater than AQ ; add to each QB ; A B therefore AC and CB are greater than AQ and QB ...
... Produce AP to meet BC in Q. Because any two sides of a triangle are together greater than the third side , ( Th . 12. ) therefore AC and CQ are greater than AQ ; add to each QB ; A B therefore AC and CB are greater than AQ and QB ...
Side 32
... Produce the side BC to D. Then because the exterior angle ACD is greater than the interior and opposite angle ABC ; add to each the angle ACB ; ( Th . 9. ) therefore the two angles ACD and ACB are greater than the two ABC and ACB . But ...
... Produce the side BC to D. Then because the exterior angle ACD is greater than the interior and opposite angle ABC ; add to each the angle ACB ; ( Th . 9. ) therefore the two angles ACD and ACB are greater than the two ABC and ACB . But ...
Side 38
... lines which meet in O , prove that the perpendiculars , from on the sides or sides produced of the triangle are equal to one another . EXERCISES ON THEOREMS OF INEQUALITY . The line that joins 38 [ BOOK I. ELEMENTARY GEOMETRY .
... lines which meet in O , prove that the perpendiculars , from on the sides or sides produced of the triangle are equal to one another . EXERCISES ON THEOREMS OF INEQUALITY . The line that joins 38 [ BOOK I. ELEMENTARY GEOMETRY .
Side 39
... Produce BD to B ' , making DB ' = DB . Join AB ' . Then since the two triangles BDC , B'DA have two sides BD , DC and the included angle BDC of the one respec- tively equal to the two sides B'D , DA and the included angle B'DA of the ...
... Produce BD to B ' , making DB ' = DB . Join AB ' . Then since the two triangles BDC , B'DA have two sides BD , DC and the included angle BDC of the one respec- tively equal to the two sides B'D , DA and the included angle B'DA of the ...
Side 42
... produced to any length both ways do not meet . Axiom 5. Two straight lines that intersect one another cannot both be parallel to the same straight line . Def . 36. A trapezium is a quadrilateral that has only one pair of opposite sides ...
... produced to any length both ways do not meet . Axiom 5. Two straight lines that intersect one another cannot both be parallel to the same straight line . Def . 36. A trapezium is a quadrilateral that has only one pair of opposite sides ...
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AB² ABCD alternate angles angle ABC angle APB angle BAC angles are equal angles equal bisector centre chord circumference coincide College Constr construct contrapositive Crown 8vo describe a circle diagonals diameter divided draw Edition equal angles equal circles equiangular Euclid exterior angle fcap Find the locus four right angles Geometry given angle given circle given line given point given rectilineal figure given straight line hypotenuse included angle inscribed intersect isosceles triangle less Let AB Let ABC locus magnitudes meet middle point minor arc opposite angles opposite sides parallel parallelogram perpendicular polygon PROBLEM produced Proof Q. E. D. THEOREM quadrilateral radius rectangle contained reflex angle required to prove rhombus right angles segment semicircle Shew square subtend supplementary supplementary angles tangent THEOREM trapezium triangle ABC triangles are equal unequal
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