Key to System of practical mathematics. 2 pt. No.xvii |
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Side 65
... prove that the figure ABCD is a parallelogram . Since the figure can be divided into two triangles , having their ... proved , that AB and DC are pa- rallel , and .. by ( Def . 38 ) the figure is a parallelogram . and A 8. Let ABCD be ...
... prove that the figure ABCD is a parallelogram . Since the figure can be divided into two triangles , having their ... proved , that AB and DC are pa- rallel , and .. by ( Def . 38 ) the figure is a parallelogram . and A 8. Let ABCD be ...
Side 66
... proved that BD ..the diagonals of a rhombus bisect each is a L , ( Def . 9. ) in E , and in the is bisected in E ; other at Ls . Q. E. D. F 10. Let ABC be a △ , whose sides AB , AC , are bisected in D and E , then the line DE is || BC ...
... proved that BD ..the diagonals of a rhombus bisect each is a L , ( Def . 9. ) in E , and in the is bisected in E ; other at Ls . Q. E. D. F 10. Let ABC be a △ , whose sides AB , AC , are bisected in D and E , then the line DE is || BC ...
Side 68
... prove that the squares of AB , B BC , CD , and DA , are together equal to the squares of AC and BD , and four times the square of EF . Q. E. D. E F D Because BAD is a A , whose base , BD , is bisected in E , the squares of BA , AD , are ...
... prove that the squares of AB , B BC , CD , and DA , are together equal to the squares of AC and BD , and four times the square of EF . Q. E. D. E F D Because BAD is a A , whose base , BD , is bisected in E , the squares of BA , AD , are ...
Side 69
... proved in the same manner that it bisects the LACB , and by Exercise 3 the drawn through the points B and O will bisect the LABC , and ( Prop . 7 , cor . 2 ) the sides AB , BC , CA , are bisected in the points F , D , and E. The | OD ...
... proved in the same manner that it bisects the LACB , and by Exercise 3 the drawn through the points B and O will bisect the LABC , and ( Prop . 7 , cor . 2 ) the sides AB , BC , CA , are bisected in the points F , D , and E. The | OD ...
Side 70
... prove that DF is = CG . Through the centre E draw the diameter LM parallel to the chord CD , and produce AF to meet it in H , and through E draw EI perpendi- cular to DC . Since each of the lines AF , BG , and EI , are to CD , they are ...
... prove that DF is = CG . Through the centre E draw the diameter LM parallel to the chord CD , and produce AF to meet it in H , and through E draw EI perpendi- cular to DC . Since each of the lines AF , BG , and EI , are to CD , they are ...
Vanlige uttrykk og setninger
a+b+c AABC ABCD acres base binomial theorem bisected centre changing the signs chord circle circumference coefficients collecting the terms completing the square cosec denominator diameter difference distance dividing divisor equal extracting the root feet find the area find the differential fraction given equation gives greater segment half the sum height hence the area hypotenuse inches inverted latitude least common multiple Let ABC Log.cosec logarithm miles Mult Multiply number sought perp perpendicular poles Problem XI Prop question radius rectangle semiperimeter sine slant slant height solidity square root substituting Subt Subtract surf Tabular area tangent Theorem third side transp transposing transposition triangle Trig value of x wherefore whole arc whole surface yards دو
Populære avsnitt
Side 74 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 75 - If the vertical angle of a triangle be 'bisected 'by a straight line which also cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Side 9 - Let x measure у by the units in n, then it will measure cy by the units in nc. 2d. If a quantity measure two others, it will measure their sum or difference. Let a be contained...
Side 15 - ... sin(a + b + c). Again (a) represents the coarse ROM, and bands b and c are two controls of the fine-tuned ROMs so that a < 90°, b < 90 • 2~a and c < 90 • 2~(a + 6). This is shown in Fig. 7-7. Sunderland showed that the trigonometric identity can be written as sin(a + b + c) = sin(a + 6) cos c + cos a cos b sin...
Side 10 - The truth of this rule depends upon these two principles ; 1". If one quantity measure another, it will also measure any multiple of that quantity. Let x measure y by the units in n, then it will measure cy by the units in nc.
Side 139 - Arc, on the Sine and Cosine of an Arc in terms of the Arc itself, and a new Theorem for the Elliptic Quadrant.
Side 137 - The differential of the logarithm of a function is equal to the differential of the function, divided by the function itself.
Side 149 - The pyramid may be conceived to be made up of an infinite number of planes parallel to ABC.
Side 81 - ... sum of any number of quantities is equal to the sum of the corresponding functions of each of these quantities, will be called distributive
Side 86 - We thus derive the following method for multiplying two binomials which have a common first term : The first term of the product is the square of the common first terms of the binomials.