The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books are Corrected, and Some of Euclid's Demonstrations are Restored. Also, the Book of Euclid's Data, in Like Manner Corrected. viz. the first six books, together with the eleventh and twelfthDesilver, Thomas & Company, 1838 - 416 sider |
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Resultat 6-10 av 100
Side 29
... shown to be equal to the angle BAC ; therefore the whole ex- terior angle ACD is equal to the two interior and opposite angles CAB , ABC ; to these equals add the angle ACB , and the angles ACD , ACB are equal to the three angles CBA ...
... shown to be equal to the angle BAC ; therefore the whole ex- terior angle ACD is equal to the two interior and opposite angles CAB , ABC ; to these equals add the angle ACB , and the angles ACD , ACB are equal to the three angles CBA ...
Side 30
... shown to be equal to it . Therefore straight lines , & c . Q. E. D. PROP . XXXIV . THEOR . THE opposite sides and angles of parallelograms are equal to one another , and the diameter bisects them , that is , divides them into two equal ...
... shown to be equal to it . Therefore straight lines , & c . Q. E. D. PROP . XXXIV . THEOR . THE opposite sides and angles of parallelograms are equal to one another , and the diameter bisects them , that is , divides them into two equal ...
Side 31
... shown to be equal to the angle BDC ; therefore the opposite sides and angles of parallelograms are equal to one another ; also , their diameter bisects them ; for AB being equal to CD , and BC common , the two AB , BC are equal to the ...
... shown to be equal to the angle BDC ; therefore the opposite sides and angles of parallelograms are equal to one another ; also , their diameter bisects them ; for AB being equal to CD , and BC common , the two AB , BC are equal to the ...
Side 54
... shown , that no other point but F is the centre ; that is , F is the centre of the circle ABC . Which was to be found . C ། G F B D E COR . From this it is manifest , that if in a circle a straight line bisect another at right angles ...
... shown , that no other point but F is the centre ; that is , F is the centre of the circle ABC . Which was to be found . C ། G F B D E COR . From this it is manifest , that if in a circle a straight line bisect another at right angles ...
Side 55
... , it shall cut it at right ( 3. 3. ) angles ; wherefore FEB is a right angle , and FEA was shown to be a right angle ; therefore FEA E B C is equal to the angle FEB , the less to BOOK III . 55 THE ELEMENTS OF EUCLID .
... , it shall cut it at right ( 3. 3. ) angles ; wherefore FEB is a right angle , and FEA was shown to be a right angle ; therefore FEA E B C is equal to the angle FEB , the less to BOOK III . 55 THE ELEMENTS OF EUCLID .
Vanlige uttrykk og setninger
altitude angle ABC angle BAC base BC BC is equal BC is given bisected centre circle ABCD circumference Co-S cone cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid ex æquali excess fore given angle given in magnitude given in position given in species given magnitude given ratio given straight line gles gnomon join less Let ABC multiple parallel parallelogram parallelogram AC perpendicular point F polygon prism proportionals proposition pyramid Q. E. D. PROP radius ratio of AE rectangle CB rectangle contained rectilineal figure remaining angle right angles segment sides BA similar sine solid angle solid parallelopiped square of AC square of BC straight line AB straight line BC tangent THEOR third triangle ABC triplicate ratio vertex wherefore
Populære avsnitt
Side 45 - Ir a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Side 41 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 54 - Ir any two points be taken in the circumference of a circle, the straight line which joins them shall fall within the circle. Let ABC be a circle, and A, B any two points in the circumference ; the straight line drawn from A to B shall fall within the circle.
Side 18 - ABD, the less to the greater, which is impossible ; therefore BE is not in the same straight line with BC.
Side 10 - From a given point to draw a straight line equal to a given straight line. Let A be the given point, and BC the given straight line: it is required to draw from the point A a straight line equal to BC.
Side 8 - Let it be granted that a straight line may be drawn from any one point to any other point.
Side 256 - Again ; the mathematical postulate, that " things which are equal to the same are equal to one another," is similar to the form of the syllogism in logic, which unites things agreeing in the middle term.
Side 129 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 23 - At a given point in a given straight line, to make a rectilineal angle equal to a given rectilineal angle. Let AB be the given straight line, and A...
Side 20 - ANY two angles of a triangle are together less than two right angles.