The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
Inni boken
Resultat 6-10 av 64
Side 13
... A B , A C , equal to the two sides , DE , DF , each to each , viz . AB to DE , and A AC to DF , and also the base BC ... straight line BC upon EF ; the point C shall also coincide with the point BC because BC is equal to EF ( Hyp ...
... A B , A C , equal to the two sides , DE , DF , each to each , viz . AB to DE , and A AC to DF , and also the base BC ... straight line BC upon EF ; the point C shall also coincide with the point BC because BC is equal to EF ( Hyp ...
Side 14
... A B , and from AC cut ( 1. 3. ) off A E equal to A D ; join D E , and upon it , on the side towards B and C , describe ( 1. 1. ) an equilateral tri- angle DEF ; then join AF ; the straight line AF bisects the triangle BA C. Because A D ...
... A B , and from AC cut ( 1. 3. ) off A E equal to A D ; join D E , and upon it , on the side towards B and C , describe ( 1. 1. ) an equilateral tri- angle DEF ; then join AF ; the straight line AF bisects the triangle BA C. Because A D ...
Side 15
... line , that is , to divide it into two equal parts . Let A B be the given straight line ; it is required to divide it into two equal parts . Describe ( 1. 1. ) upon it an equilateral triangle A B C , and bisect ( 1. 9. ) the angle A C B ...
... line , that is , to divide it into two equal parts . Let A B be the given straight line ; it is required to divide it into two equal parts . Describe ( 1. 1. ) upon it an equilateral triangle A B C , and bisect ( 1. 9. ) the angle A C B ...
Side 16
... straight line AB , FC has been drawn at right angles to AB . Which was to be done . COR . By help of this problem , it may be demon- strated that two straight lines cannot have a common segment . E If it be possible , let the two straight ...
... straight line AB , FC has been drawn at right angles to AB . Which was to be done . COR . By help of this problem , it may be demon- strated that two straight lines cannot have a common segment . E If it be possible , let the two straight ...
Side 17
... straight line cH , drawn from the given point c , is perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the two sides FH , HC are equal to the two GH , HC , each to ...
... straight line cH , drawn from the given point c , is perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the two sides FH , HC are equal to the two GH , HC , each to ...
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The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |
The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |
Vanlige uttrykk og setninger
A B C ABCD adjacent angles angle ABC angle ACB angle BAC angle equal angles BGH base BC BC is equal bisect centre circle ABC circumference diameter divided double draw a straight equal angles equal circles equal straight lines equal to FB exterior angle given point given rectilineal angle given straight line gnomon greater half a right hypotenuse interior and opposite isosceles triangle less Let ABC Let the straight line be drawn opposite angles parallel parallelogram perpendicular PROB produced Q. E. D. PROP rectangle AE rectangle contained rectilineal figure remaining angle right angles segment semicircle side BC square of AC straight line AB straight line AC straight line drawn THEOR touches the circle trapezium triangle ABC twice the rectangle vertex vertical angle