The Elements of Euclid: Viz the First Six Books, Together with the Eleventh and Twelfth, the Errors by which Theon Or Others Have Long Ago Vitiated These Books, are Corrected, and Some of Euclid's Demonstrations are Restored : Also the Book of Euclid's Data, in Like Manner CorrectedP. Wogan, 1803 - 520 sider |
Inni boken
Resultat 6-10 av 100
Side 39
... third angle of the one to the third angle of the other " , viz . the fide b 26. 1 . AB to the fide CD , and AC to BD , and the angle BAC equal to the angle BDC : And because the angle ABC is equal to the angle BCD , and the angle CBD to ...
... third angle of the one to the third angle of the other " , viz . the fide b 26. 1 . AB to the fide CD , and AC to BD , and the angle BAC equal to the angle BDC : And because the angle ABC is equal to the angle BCD , and the angle CBD to ...
Side 73
... third , BE , EF are greater than BF ; but AE a 20. I. is equal to EB ; therefore AE , EF that is , AF is greater than BF : Again , becaufe BE is equal to CE , and FE common to the triangles BEF , CEF , the two fides BE , EF are equal to ...
... third , BE , EF are greater than BF ; but AE a 20. I. is equal to EB ; therefore AE , EF that is , AF is greater than BF : Again , becaufe BE is equal to CE , and FE common to the triangles BEF , CEF , the two fides BE , EF are equal to ...
Side 111
... third angle . Which was to be done . • PROP . XI . PROB . O infcribe an equilateral and equiangular pentagon in a given circle . a Let ABCDE be the given circle ; it is required to inscribe . an equilateral aud equiangular pentagon in ...
... third angle . Which was to be done . • PROP . XI . PROB . O infcribe an equilateral and equiangular pentagon in a given circle . a Let ABCDE be the given circle ; it is required to inscribe . an equilateral aud equiangular pentagon in ...
Side 113
... third angle to the third angle ; Therefore the ftraight line KC is equal to CL , and the angle FKC to the angle FLC : And because KC is equal to CL , KL is double of KČ In the fame manner , it may be shown that HK is double of BK : And ...
... third angle to the third angle ; Therefore the ftraight line KC is equal to CL , and the angle FKC to the angle FLC : And because KC is equal to CL , KL is double of KČ In the fame manner , it may be shown that HK is double of BK : And ...
Side 116
... third part of two right angles ; In the fame manner it may be demonftrated that the angle DGC is alfo the third part of two right angles : And because the ftraight line GC makes with EB the adjacent angles EGC , CGB equal c to two right ...
... third part of two right angles ; In the fame manner it may be demonftrated that the angle DGC is alfo the third part of two right angles : And because the ftraight line GC makes with EB the adjacent angles EGC , CGB equal c to two right ...
Andre utgaver - Vis alle
The Elements of Euclid, Viz: The Errors, by Which Theon, Or Others, Have ... Robert Simson,Robert Euclid Ingen forhåndsvisning tilgjengelig - 2018 |
The Elements of Euclid, Viz: The Errors, by Which Theon, Or Others, Have ... Robert Simson,Robert Euclid Ingen forhåndsvisning tilgjengelig - 2015 |
The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Robert Simson Ingen forhåndsvisning tilgjengelig - 2017 |
Vanlige uttrykk og setninger
AC is equal alfo alſo angle ABC angle BAC bafe baſe BC is given becauſe the angle becauſe the ratio bifected Book XI cafe centre circle ABCD circumference cone confequently cylinder defcribed demonftrated diameter drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fide BC fides fimilar fince firft firſt folid angle fome fore fphere fquare of AC ftraight line AB given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs leſs likewife line BC muſt parallel parallelogram parallelopipeds perpendicular polygon prifms propofition proportionals pyramid rectangle contained rectilineal figure right angles ſquare thefe THEOR theſe tiple triangle ABC vertex wherefore