## Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids; to which are Added Elements of Plane and Spherical TrigonometryW. E. Dean, 1851 - 317 sider |

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Resultat 6-10 av 100

Side 18

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**Wherefore**, from the given point C , in the given straight line AB , FC has been drawn at right angles to AB . PROP . XII . PROB . To draw a straight line perpendicular to a given straight line , of an unlimited length , from a given ... Side 21

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**wherefore**the angle BAE is equal to the angle ECF ; but the angle ECD is greater than the an- gle ECF ; therefore the angle ECD , that is ACD , is greater than BAE : In the same manner , if the side BC be bisected , it may be ... Side 22

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**wherefore**much more is the angle ABC greater than ACB PROP . XIX . THEOR . The greater angle of every triangle is subtended by the greater side , or has the greater side opposite to it . Let ABC be a triangle , of which the angle ABC is ... Side 26

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**wherefore**also the angle BCG is equal to the angle BCA , the less to the greater , which is impossible ; therefore AB is not unequal to DE , that is , it is equal to it ; and BC is equal to EF ; therefore the two AB , BC are equal to ... Side 27

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**wherefore**BC is not unequal to EF , that is , it is equal to it ; and AB is equal to DE ; therefore the two , AB , BC are equal to the two DE , EF , each to each ; and they contain equal angles ;**wherefore**the base AC is equal to the ...### Andre utgaver - Vis alle

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Elements of Geometry: Containing the First Six Books of Euclid, with a ... John Playfair Uten tilgangsbegrensning - 1836 |

### Vanlige uttrykk og setninger

ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated described diameter divided draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given rectilineal given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROB PROP proportional proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR touches the circle triangle ABC triangle DEF wherefore