The school edition. Euclid's Elements of geometry, the first six books, by R. Potts. corrected and enlarged. corrected and improved [including portions of book 11,12]. |
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Resultat 6-10 av 88
Side 31
And because the angle ABC is equal to the angle BCD , and the angle CBD to
the angle ACB , therefore the whole angle ABD is equal to the whole angle ACD ;
( ax . 2 . ) and the angle BAC has been shewn to be equal to BDC ' ; therefore the
...
And because the angle ABC is equal to the angle BCD , and the angle CBD to
the angle ACB , therefore the whole angle ABD is equal to the whole angle ACD ;
( ax . 2 . ) and the angle BAC has been shewn to be equal to BDC ' ; therefore the
...
Side 32
... therefore the whole , or the remainder AE , is equal to the whole , or the
remainder DF ; ( ax . 2 or 3 . ) and AB is equal to DC ; ( 1 . 24 . ) hence in the
triangles EAB , FDC , because FD is equal to EA , and DC to AB , and the exterior
angle ...
... therefore the whole , or the remainder AE , is equal to the whole , or the
remainder DF ; ( ax . 2 or 3 . ) and AB is equal to DC ; ( 1 . 24 . ) hence in the
triangles EAB , FDC , because FD is equal to EA , and DC to AB , and the exterior
angle ...
Side 36
... equal to one another . Let ABCD be a parallelogram , of which the diameter is
AC : and EH , GF the parallelograms about AC , that is , through which A C
passes : also BK , KD the other parallelograms which make up the whole figure
ABCD ...
... equal to one another . Let ABCD be a parallelogram , of which the diameter is
AC : and EH , GF the parallelograms about AC , that is , through which A C
passes : also BK , KD the other parallelograms which make up the whole figure
ABCD ...
Side 37
but the whole triangle ABC is equal to the whole triangle ADC ; therefore the
remaining complement BK is equal to the remaining complement KD . ( ax . 3 . )
Wherefore the complements , & c . Q . E . D . PROPOSITION XLIV . PROBLEM .
but the whole triangle ABC is equal to the whole triangle ADC ; therefore the
remaining complement BK is equal to the remaining complement KD . ( ax . 3 . )
Wherefore the complements , & c . Q . E . D . PROPOSITION XLIV . PROBLEM .
Side 39
and FL has been proved parallel to KU , . wherefore the figure FKML is a
parallelogram ; and since the parallelogram HF is equal to the triangle ABD , and
the parallelogram GM to the triangle BDC ; therefore the whole parallelogram
KFLM is ...
and FL has been proved parallel to KU , . wherefore the figure FKML is a
parallelogram ; and since the parallelogram HF is equal to the triangle ABD , and
the parallelogram GM to the triangle BDC ; therefore the whole parallelogram
KFLM is ...
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Vanlige uttrykk og setninger
ABCD Algebraically Apply base bisected Book chord circle circumference common construction contained definition demonstrated described diagonals diameter difference distance divided double draw drawn equal equal angles equiangular equilateral triangle equimultiples Euclid extremities fall figure formed four fourth Geometrical given circle given line given point given straight line greater half Hence inscribed intersection isosceles join length less Let ABC line drawn magnitudes manner mean meet multiple parallel parallelogram pass perpendicular plane problem produced Prop proportionals proved Q.E.D. PROPOSITION radius ratio reason rectangle rectangle contained regular remaining respectively right angles segment semicircle shew shewn sides similar solid square straight line taken tangent THEOREM third touch triangle ABC twice units vertex wherefore whole
Populære avsnitt
Side 112 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.
Side 83 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square...
Side 48 - If two triangles have two sides of the one equal to two sides of the other, each to each ; and...
Side 238 - The first of four magnitudes is said to have the same ratio to the second, which the third has to the fourth, when any equimultiples whatsoever of the first and third being taken, and any equimultiples whatsoever of the second and fourth; if the multiple of the first be less than that of the second, the multiple of the third is also less than that of the fourth...
Side 198 - A LESS magnitude is said to be a part of a greater magnitude, when the less measures the greater, that is, ' when the less is contained a certain number of times exactly in the greater.
Side 271 - SIMILAR triangles are to one another in the duplicate ratio of their homologous sides.
Side 81 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 115 - angle in a segment' is the angle contained by two straight lines drawn from any point in the circumference of the segment, to the extremities of the straight line which is the base of the segment.
Side 341 - On the same base, and on the same side of it, there cannot be two triangles...
Side 24 - ... twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many right angles as the figure has sides.
Bibliografisk informasjon
| Tittel | The school edition. Euclid's Elements of geometry, the first six books, by R. Potts. corrected and enlarged. corrected and improved [including portions of book 11,12]. |
| Forfatter | Euclides |
| Redaktør | Robert Potts |
| Utgave | 5 |
| distribuert | 1864 |
| Original fra | Oxford University |
| Digitalisert | 7. sep 2006 |
| Eksporter sitat | BiBTeX EndNote RefMan |