 | Joseph Ray - 1852 - 408 sider
...What two numbers are those whose sum is 20 and product 36 ? Ans. 2 and 18. 6. Divide the number 15 into two such parts that their product shall be to...sum of their squares, in the ratio of 2 to 5. Ans. 5 and 10. 7. Find a number such, that if you subtract it from 10, and multiply the remainder by the... | |
 | Benjamin Greenleaf - 1852 - 348 sider
...8 to the less, they will then be to each other as 6 to 5. What are the numbers ? Ans. 20 and 12. 5. Divide the number 60 into two such parts that their product shall be to the difference of their squares as 2 to 3. Ans. 40 and 20. . 6. I have two square house lots, which, together,... | |
 | Elias Loomis - 1855 - 356 sider
...numbers are those whose difference is 2a, and product b ? Ans. a± Va'+b, and — a± Va'+b. Prob. 4. It is required to divide the number 60 into two such parts that their product shall be 864. Let x = one of the parts. Then will 60— a; = the other part. And by the question, a; (60—... | |
 | 1855 - 424 sider
...difference, sum and product, are as the numbers 2, 3 and 6, respectively ? Prob. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference between the quantities of each... | |
 | Elias Loomis - 1856 - 280 sider
...180, and the third 315 men. Prob. 39. Divide the number 60 into two such parts that their product may be to the sum of their squares in the ratio of 2 to 5. Ans. 20 and 40. it from 10, and multiply the remainder oy the number itself, the product shall be 21. Ans. 7 or 3.... | |
 | Archibald Montgomerie - 1857 - 116 sider
...of the greater shall exceed three times the square of the less by 95. Ans. 11, and 7. (15.) Divide 60 into two such parts that their product shall be...their squares in the ratio of 2 to 5. Ans. 20, and 40. (16.) Divide 225 into two such parts that the sum of their square roots shall be 21. Ans. 144, and... | |
 | James B. Dodd - 1859 - 368 sider
...the time past noon was $• of the time till midnight ; what was the hour ? Ans. 48 min. past 4. 33. It is required to divide the number 60 into two such parts that their product shall be equal to 3 times the square of the less ; what are the parts ? Ans. 15 and 45. 34. How much wine at... | |
 | James William Dodd - 1859 - 188 sider
...the conditions of the problem, we have the Equation which will give z = 4A hours = 4/t. 48??i. 33. It is required to divide the number 60 into two such parts, that their product shall be equal to the square of the less. What are the parts ? Let x represent the less part ; then 60 — x... | |
 | Theodore Strong - 1859 - 570 sider
...is /j _ о ¿s not greater than у --- 11. To divide the number or quantity 2л into two parts. such that their product shall be to the sum of their squares, in the ratio of m to n. Since the parts may be expressed by a + (c and a — ж, their product and the sum of their... | |
 | Benjamin Greenleaf - 1863 - 338 sider
...the number 40 into two such parts, that the sum of their squares shall be 818. Ans. 23 and 17. 13. Divide the number 60 into two such parts, that their...their squares in the ratio of 2 to 5. Ans. 20 and 40. The last two Problems, as well as some others, lead to pure quadratic equations, when we let x —... | |
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It is required to divide the number 60 into two such parts, that their product shall be to the sum of their squares in the ratio of 2 to 5. 
