 | Euclides - 1879 - 146 sider
...this formula in terms corresponding to the enunciation of the proposition.] PROPOSITION III. THEOREM. If a straight line be divided into any two parts,...contained by the two parts, together with the square on the aforesaid part. Let AB be divided into any two parts at C. Then rect. AB, BC == rect. AC, BC,... | |
 | W J. Dickinson - 1879 - 44 sider
...Deduce from this that a square on a straight line is equal to four times the square on half the line. 3. If a straight line be divided into any two parts,...contained by the two parts, together with the square on the aforesaid part 1G Same proposition. Divide a given line so that the rectangle contained by the... | |
 | 1880 - 160 sider
...described upon the other two sides of it ; the angle contained by these two sides is a right angle. 7. If -a straight line be divided into any two parts,...contained by the two parts, together with the square on the aforesaid part. 8. If a straight line be divided into any two parts, the squares on the whole... | |
 | Euclides, Frederick Burn Harvey - 1880 - 178 sider
...rectangles contained by MN and MO, and by MN and NO, together = the square on MN. PBOP. III. THEOREM. If a straight line be divided into any two parts,...contained by the two parts, together with the square on the aforesaid part. Let AB be a straight line divided into any two parts in C. Then it is to be... | |
 | Isaac Todhunter - 1880 - 426 sider
...line lie divided into any ttco parts, the rectangle contained by tlie whole and one of the parts, u equal to the rectangle contained by the two parts, together with the square on the aforesaid part. Let the straight line AB be divided into any two parts at the point C: the rectangle... | |
 | Euclides - 1881 - 236 sider
...when the two straight lines mentioned in Us enunciation are equal, their rectangle is a square. FK If a straight line be divided into any two parts,...by the two parts, together with the square of the foresaid part. Let the straight line AB be divided into any two parts at the point C. The rectangle... | |
 | Isaac Sharpless - 1882 - 286 sider
...but and and AF+CE=AE; AF=AD.AC=AB.AC, CE=CF. CB =AB. CB, AB.AC+AB.CB = Proposition 3. Theorem. — If a straight line be divided into any two parts,...aforesaid part. Let the straight line AB be divided in two parts in the point C, then AB.BC=AC.CB+BC\ GEOMETRY.—BOOK II. Then but also, and AE=AD+CE;... | |
 | Marianne Nops - 1882 - 278 sider
...AC, and AB, CB = sq. on AB. Wherefore if a straight line, &c. — QED *2 PROPOSITION III., THEOREM 3. If a straight line be divided into any two parts the...contained "by the two parts, together with the square on the aforesaid part. Let the straight line AB be divided into any two parts at C. The rect. AB, BC... | |
 | 1882 - 498 sider
...subtending the right angle is equal to the squares described on the sides which contain the right angle. 14. If a straight line be divided into any two parts,...contained by the two parts, together with the square on the aforesaid part. 15. Find the centre of a circle. 16. If in a circle two straight lines cut one... | |
 | Mary W I. Shilleto - 1882 - 418 sider
...another. What is the greatest value which these complements can have for a given parallelogram ? 4. If a straight line be divided into any two parts,...contained by the two parts, together with the square on the aforesaid part. If from one of the equal angles of an isosceles triangle a perpendicular be... | |
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If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part. 
