| W J. Dickinson - 1879 - 36 sider
...Deduce from this that a square on a straight line is equal to four times the square on half the line. 3. **If a straight line be divided into any two parts,...contained by the two parts, together with the square** on the aforesaid part 1G Same proposition. Divide a given line so that the rectangle contained by the... | |
| 1880 - 144 sider
...described upon the other two sides of it ; the angle contained by these two sides is a right angle. 7. **If -a straight line be divided into any two parts,...contained by the two parts, together with the square** on the aforesaid part. 8. If a straight line be divided into any two parts, the squares on the whole... | |
| Euclid, F. B. Harvey - 1880 - 119 sider
...rectangles contained by MN and MO, and by MN and NO, together = the square on MN. PBOP. III. THEOREM. **If a straight line be divided into any two parts,...contained by the two parts, together with the square** on the aforesaid part. Let AB be a straight line divided into any two parts in C. Then it is to be... | |
| Isaac Todhunter - 1880 - 400 sider
...line lie divided into any ttco parts, the rectangle contained by tlie whole and one of the parts, u **equal to the rectangle contained by the two parts, together with the square** on the aforesaid part. Let the straight line AB be divided into any two parts at the point C: the rectangle... | |
| Euclides - 1881
...when the two straight lines mentioned in Us enunciation are equal, their rectangle is a square. FK **If a straight line be divided into any two parts,...by the two parts, together with the square of the** foresaid part. Let the straight line AB be divided into any two parts at the point C. The rectangle... | |
| Isaac Sharpless - 1882 - 266 sider
...but and and AF+CE=AE; AF=AD.AC=AB.AC, CE=CF. CB =AB. CB, AB.AC+AB.CB = Proposition 3. Theorem. — **If a straight line be divided into any two parts,...aforesaid part. Let the straight line AB be divided** in two parts in the point C, then AB.BC=AC.CB+BC\ GEOMETRY.—BOOK II. Then but also, and AE=AD+CE;... | |
| Marianne Nops - 1882
...AC, and AB, CB = sq. on AB. Wherefore if a straight line, &c. — QED *2 PROPOSITION III., THEOREM 3. **If a straight line be divided into any two parts the...contained "by the two parts, together with the square** on the aforesaid part. Let the straight line AB be divided into any two parts at C. The rect. AB, BC... | |
| 1882
...subtending the right angle is equal to the squares described on the sides which contain the right angle. 14. **If a straight line be divided into any two parts,...contained by the two parts, together with the square** on the aforesaid part. 15. Find the centre of a circle. 16. If in a circle two straight lines cut one... | |
| Mary W I. Shilleto - 1882
...another. What is the greatest value which these complements can have for a given parallelogram ? 4. **If a straight line be divided into any two parts,...contained by the two parts, together with the square** on the aforesaid part. If from one of the equal angles of an isosceles triangle a perpendicular be... | |
| 1883
...construct a triangle ADE equal to ABC, and having the common angle A. 2. If a straight line be diveded **into any two parts, the rectangle contained by the...contained by the two parts, together with the square** on the aforesaid part. 3. To divide a given straight line into two parts, so that the rectangle contained... | |
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