| Charles Reiner - 1837 - 215 sider
...SECTION IV. two angles of the one is equal to the sum of the remaining two angles of the other. 2. **If two triangles have two angles of the one equal to two angles of the other, each to each,** the third angle of the one is equal to the third angle of the other ; that is, the triangles are equiangular.... | |
| Charles Reiner - 1837 - 215 sider
...and if the equal angles be subtracted from these equals, the remaining angles must be equal. M.—If **two triangles have two angles of the one equal to two angles of the other, each to each,** what may be said of the remaining third angles ? P.—They must be equal,—for the reason alleged... | |
| William Whewell - 1837 - 182 sider
...angle; therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the **triangles have two angles of the one equal to two angles of the other** ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
| Euclides - 1837 - 88 sider
...be > Z EOF. PROPOSITION XXVI. (Argument ad absurdum). Theorem. If two triangles have two angles of **one equal to two angles of the other, each to each, and one** side equal to one side; viz., either the sides adjacent to the equal angles, or opposite to the equal... | |
| Andrew Bell - 1837 - 240 sider
...by BD ; and because the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD, **have two angles of the one equal to two angles of the other** ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| Euclid, James Thomson - 1837 - 390 sider
...is equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD, FBD **have two angles of the one equal to two angles of the other,** and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| A. Bell - 1837 - 164 sider
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore **two angles of the one equal to two angles of the other,** and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
| Euclides - 1838
...that the <UAx. right angle BED is equalt to the right angle BFD ; therefore the two triangles EBD, FBD **have two angles of the one equal to two angles of , the other, each to each ; and** the side BD, B Tf C •which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| Euclid, Robert Simson - 1838 - 416 sider
...bisected by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD **have two angles of the one equal to two angles of the other,** and the side BD, which is opposite to one of the equal angles in each is common to both ; therefore... | |
| Thomas Kerigan - 1838
...the angle BCD, by the aforesaid proposition. And because the two triangles ADF and BCF have, thus, **two angles of the one equal to two angles of the other,** viz., the angle FAD to the angle FB C, and the angle AD F to the angle BCF; and the side AF of the... | |
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