 | Euclides - 1841 - 351 sider
...* 15. 1. angle EBC: and the angle AEG is equal* to the angle BEH; therefore the triangles AEG, BEH have two angles of the one equal to two angles of the other, each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another: therefore their other * 28. 1.... | |
 | Chambers W. and R., ltd - 1842
...proposition gives still further information on this useful subject. It shows that if two triangle* have two angles of the one equal to two angles of the other, each to each, and one side equal to one aide, namely, either the sides adjacent to the equal angles, or the sides opposite... | |
 | 1842
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding sides... | |
 | 1842
...course) alone are • enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to • the corresponding... | |
 | 1842
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding sides... | |
 | Euclides - 1842
...bisected by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | John Playfair - 1842 - 317 sider
...by BD ; and because the right angle BED, is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | Euclides - 1845
...the right angle BED is equal to the right angle BFD ; (ax. 11.) therefore the two triangles EBD, FBD have two angles of the one equal to two angles of the other, each to each ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore their... | |
 | Euclid, James Thomson - 1845 - 352 sider
...is equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD. FBD have two angles of the one equal to two angles of the other, each to each, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore (I.... | |
 | Scottish school-book assoc - 1845
...1), and the side BC is = the side BA, being sides of an equilateral triangle ; .-. the Д» CBD, ABE, have two angles of the one equal to two angles of the other, and a side lying between these equal angles also equal ; .-• these triangles are equal in every respect,... | |
| |
If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal... 
