 | Francis Walkingame - 1833 - 204 sider
...sides only are given. — From half the sum of the sides subtract each side severally: multiply the half sum and the three remainders continually together ; and the square root of their product will be the area. (3) The three sides of a triangular fish-pond, are 140, 336, and 415... | |
 | John Bonnycastle - 1835 - 308 sider
...(c2 — a — ft2), and the area J ABX CD = ii/ (a + V — c2) X (c2— a — _62) 2. Multiply the half sum and the three remainders continually together^ and the square root of the product will he the area required. EXAMPLES. 1. Required the area of the triangle ABC, whose three sides BC, CA,... | |
 | John Hind - 1837 - 584 sider
...the sum of the sides, subtract each side separately: multiply the half sum and the three remainders together, and the square root of the product will be the area. Ex. 4. Required the area of a triangle whose sides are \2a* +262-c2, \A a2 + 2 c2 - b", and By the... | |
 | Thomas Holliday - 1838 - 404 sider
...practice. Rule.—From half the sum of the three sides subtract cacli side separately; multiply the half sum and the three remainders continually together, and the square root of the last product will be the area. PHOBLEM VII. TO FIND THE AREA OF A TRAPEZIUM. Rule.—Multiply the diagonal... | |
 | Frederick Augustus Griffiths - 1839 - 348 sider
...sum of the three sides, subtract each side severally; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Two sides of a right angled triangle being given to find the third side.—When the two sides... | |
 | William Ruger - 1841 - 268 sider
...side severally, and multiply the half of the sum and these remainders, and the square root of this product will be the area of the triangle. EXAMPLES. 1. Required the area of an oblique triangle, the 3 sides of which are 13, 14, and 15 rods. Ans. 84 square rods. 13 21 21 21... | |
 | John M'Nevin - 1841 - 300 sider
...sum, subtract each side severally; from the half sum multiply the half sum and the three differences together, and the square root of the product will be the area. 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans.... | |
 | John M'Nevin - 1841 - 300 sider
...sum, subtract each side severally; from the half sum multiply the half sum and the three differences together, and the square root of the product will be the area. 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans.... | |
 | Charles Haynes Haswell - 1844 - 298 sider
...the sum of the three sides subtract each side separately ; then multiply the half sum and the \hree remainders continually together, and the square root of the product will be the To find the Length of one side of a Right-angled Triangle, when the Length of the other two sides are... | |
 | William Watson (of Beverley.) - 1845 - 188 sider
...pieces of wood, to the crooked fence, so as to include as much on one side as they exclude on the other. remainders continually together, and the square root of the product will be the area. EXAMPLES. I . Required the area of a triangle, the sides of which are 26, 28, and 30. 26 28 42 42 42... | |
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Multiply the half sum and the three remainders continually together, and the square root of the product will be the area... 
