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" If two triangles have an angle of one equal to an angle of the other, their areas are to each other as the products of the sides including the equal angles. Given two triangles ABC and A'B'C', having the angle A equal to the angle A'. "
The Elements of Plane Geometry - Side 180
av Charles Austin Hobbs - 1899 - 240 sider
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Annual Report of the Department of Education to the General Assembly of the ...

Georgia. Department of Education - 1919 - 648 sider
...triangle the square of the hypotenuse is1 equal to the sum of the squares of the legs. Demonstrate: If two triangles have an angle of one equal to an angle of the other, their areas are to each other as the products of the sides including the equal angles. Demonstrate:...
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A School Geometry

Henry Sinclair Hall - 1924 - 316 sider
...beginning. (2) The step from (i) to (ii) assumes that if XY : AB - XZ : AC then XY:XZ=AB: AC. THEOREM XV. If two triangles have an angle of one equal to an angle of the other, and the sides containing the equal angles proportional, then the triangles are similar. Given. ABC, XYZ...
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Texas School Journal, Volum 21

1903 - 780 sider
...triangle to the point in which its medians concur, is one-third of the original triangle. 6. Prove: If two triangles have an angle of one equal to an angle of the other, they are proportional to the rectangles of the sides including those angles. 722 EXAMINATION QUESTIONS....
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Plane Geometry

William Betz, Harrison Emmett Webb, Percey Franklyn Smith - 1912 - 356 sider
...72, 72, 60, 44, 36, 28, and 20, measurements being in centimeters. 209 PROPOSITION IV. THEOREM 337. If two triangles have an angle of one equal to an angle of the other, their areas are to each other as the products of the sides including the equal angles. Given two triangles...
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Plane Geometry

Royal A. Avery - 1925 - 360 sider
...circle at D, the diameter is the mean proportional between AC and AD. Proposition IX. Theorem 308. // two triangles have an angle of one equal to an angle of the other and the sides including these angles proportional, the triangles are similar. Given: The A/1BC and A'B'C'...
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