 | Euclid - 1838 - 470 sider
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off A from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because... | |
 | Robert Simson - 1838 - 434 sider
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off A from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because... | |
 | Euclides - 1841 - 378 sider
...required, Let AB be the given straight line; it is required to cut off any part from it. part which U to be cut off from it; join BC, and draw DE parallel to CB: then AE shall be the part required to be cut off Because ED is parallel to BC, one of the sides... | |
 | John Playfair - 1842 - 332 sider
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC,...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the 17 B c DA : DC (4. 6.) BA : BD (46.) CA : CD (46.).... | |
 | Euclides - 1842 - 316 sider
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take A c the same multiple of AD, that AB is of the part which is to be cut off from it ; join B, c, and draw DE parallel to it (31. 1.) : then AE is the part required to be cut off. ' " " Because... | |
 | Euclid - 1845 - 218 sider
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the / same multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC ; as CD is to DA, so * 2.... | |
 | Euclides - 1845 - 546 sider
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclid, James Thomson - 1845 - 382 sider
...it. Draw a straight line AC making any angle with AB ; in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it ; .join BC, and (I. 31) draw DE parallel to it: AE is the part required. Because ED isparallel to BC, one of the sides... | |
 | Euclides - 1846 - 292 sider
...a straight line AC, making any angle with A. 13 ; and in AC take any point D, and take AC the same multiple of AD that AB is of the part which is to...DE parallel to it : then AE is the part required. For, because ED is parallel to BC, one of the sides of the triangle ABC, therefore BE is to EA as CD... | |
 | Euclid, John Playfair - 1846 - 334 sider
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC,...to it: then AE is the part required to be cut off. 130 triangle ABC, viz. to BC, CD : DA : : BE : EA (2. 6.) ; and by composition (18. 5), CA : AD : :... | |
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AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. 
