Søk Bilder Maps Play YouTube Nyheter Gmail Disk Mer »
Logg på
Bøker Bok 2130 av 48In a right angled spherical triangle, the rectangle under the radius and the sine...
" In a right angled spherical triangle, the rectangle under the radius and the sine of the middle part, is equal to the rectangle under the tangents of the adjacent parts ; or', to the rectangle under the cosines of the opposite parts. "
Trigonometry, Plane and Spherical: With the Construction and Application of ... - Side 34
av Thomas Simpson - 1810 - 125 sider
Uten tilgangsbegrensning - Om denne boken

The Complete Mathematical and General Navigation Tables: Including ..., Volum 1

Thomas Kerigan - 1828 - 664 sider
...premised, the required parts are to be computed by the two following equations ; viz., 1st. — The product of radius and the sine of the middle part, is equal to the product of the tangents of the extremes conjunct2d. — The product of radius and the sine of the middle...
Uten tilgangsbegrensning - Om denne boken

A London Encyclopaedia, Or Universal Dictionary of Science, Art ..., Volum 22

Thomas Curtis - 1829
...complement С are adjoining, and AB and В С opposite extremes. With these explanations Napier's rules are 1. The rectangle of radius and the sine of the middle part is equal to the rectangle of the tangents of the adjoining extremes. 2. The rectangle of radius and the sine of the middle part is equal...
Uten tilgangsbegrensning - Om denne boken

The Edinburgh Encyclopædia Conducted by David Brewster, with the ..., Volum 18

1832
...is equal to the rectangle under the tangents of the adjacent extremes." 2. "The rectangle under the radius and the sine of the middle part is equal to the rectangle under the cosines of the opposite extremes." The radius being unity does not appear in the formulae....
Uten tilgangsbegrensning - Om denne boken

Elements of Geometry: Containing the First Six Books of Euclid : with a ...

John Playfair - 1832 - 333 sider
...contained in the following PROPOSITION. In a right angled spherical triangle, the rectangle under the radius and the sine of the middle part, is equal to the rectangle under the tangents of the adjacent parts; or to the rectangle under the cosines of the opposite parts....
Uten tilgangsbegrensning - Om denne boken

Mathematical and Astronomical Tables: For the Use of Students in Mathematics ...

William Galbraith - 1834 - 428 sider
...obtained by the following THEOREM. In any right-angled spherical triangle, the rectangle under the radius, and the sine of the middle part is equal to the rectangle under the tangents of the adjacent parts ; or to the rectangle under the COSINES of the OPPOSITE parts....
Uten tilgangsbegrensning - Om denne boken

The Elements of Euclid: viz. the first six books, together with the eleventh ...

Euclid, Robert Simson - 1835 - 513 sider
...angled spherical triangles are resolved with the greatest ease. RULE I. THE rectangle contained by the radius and the sine of the middle part, is equal to the rectangle contained by the tangents of the adjacent parts. RULE II. THE rectangle contained by the radius, and...
Uten tilgangsbegrensning - Om denne boken

Elements of Geometry and Trigonometry

Adrien Marie Legendre - 1836 - 359 sider
...Making A =90°, we have sin B sin C cos a=R cos B cos C, or R cos a=cot B cot C ; that is, radius into the sine of the middle part is equal to the rectangle of the tangent of the complement of B into the tangent ot the complement of C, that is, to the rectangle of...
Uten tilgangsbegrensning - Om denne boken

Elements of Geometry: Containing the First Six Books of Euclid : with a ...

John Playfair - 1837 - 318 sider
...contained in the following PROPOSITION. In a right angled spherical triangle, the rectangle under the radius and the sine of the middle part, is equal to the rectangle under the tangents of the adjacent parts ; or', to the rectangle under the cosines of the opposite...
Uten tilgangsbegrensning - Om denne boken

The Complete Mathematical and General Navigation Tables: Including Every ...

Thomas Kerigan - 1838
...middle part, is equal to the product of the tangents of the extremes conjunct. 2d. — Tlie product of radius and the sine of the middle part, is equal to the product of the co- sines of the extremes disjunct. Since these equations are adapted to the complements...
Uten tilgangsbegrensning - Om denne boken

Elements of Trigonometry, Plane and Spherical: Adapted to the Present State ...

Charles William Hackley - 1838 - 307 sider
...middle part is equal to the rectangle of the tangents of the adjacent parts. 2. Radius multiplied by the sine of the middle part is equal to the rectangle of the cosines of the opposite parts. Or both rules may be given thus : radius into the sine of the middle...
Uten tilgangsbegrensning - Om denne boken




  1. Mitt bibliotek
  2. Hjelp
  3. Avansert boksøk
  4. Last ned PDF