| Joseph Ray - 1866 - 420 sider
...product from the remainder. 4th. Double the terms of the foot already found for a partial divisor, divide the first term of the remainder by the first term of the divisor, and proceed in a similar manner to find the other terms. 1. Find the square root of 4ajy+12aty-f... | |
| Elias Loomis - 1868 - 386 sider
...following RULE. 1st. Arrange the terms according to the powers of some one letter ; take the square root of the first term for the first term of the required root, and subtract its square from the given polynomial. 2d. Divide the first term of the remainder by twice... | |
| James Hamblin Smith - 1869 - 412 sider
...expression 3ab + b' we obtain the full divisor За' + За6 + b'. Hence our rule proceeds thus : " Divide the first term of the remainder by the first term of the divisor and add the result to the first term of the roof. Tlien SA 10 take three times the product... | |
| Robert Wallace - 1870 - 164 sider
...Multiply the whole divisor by this term of the quotient, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor for a second term of the quotient ; multiply as before, and subtract the product from the first... | |
| James Hamblin Smith - 1872 - 454 sider
...expression 3<t6+62 we .obtain the full divisor 3a2+3a6 + 63. Hence our rule proceeds thus : "Diside the first term of the remainder by the first term of the divisor and add the result to the first term of the root. Then take three times tl*e product of tlie... | |
| Elias Loomis - 1873 - 396 sider
...the following RULE. Arrange the terms according to the powers of one of the letters, and take the mth root of the first term for the first term of the required root. Subtract the mth power of this term of the root from the given polynomial, and divide the first term of the remainder... | |
| William Guy Peck - 1875 - 348 sider
...of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. III. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product... | |
| James Cahill (of Dublin.) - 1875 - 230 sider
...(1) Arrange the terms according to the descending powers of one of thp letters. (») Take the square root of the first term for the first term of the required root, and subtract its square from the given quantity. (3) Take twice the part of the root already found... | |
| Edward Olney - 1877 - 466 sider
...DIVISION, TAKE THE BOOT OF THE FIBST TEBM, FOB THE FIRST TERM OF THE REQUIRED BOOT. SUBTRACT THE POWER FBOM THE GIVEN QUANTITY, AND DIVIDE THE FIRST TERM OF THE REMAINDER BY THE FIBST TERM OF THE BOOT INVOLVED TO THE NEXT INFERIOR POWER, AND MULTIPLIED BY THE INDEX OF THE GIVEN... | |
| Elias Loomis - 1879 - 398 sider
...following • RULE. Arrange the terms according to the powers of one of the letters, and take the mth root of the first term for the first term of the required root. Subtract the mth power of this term of the root from the given polynomial, and divide the first term of the remainder... | |
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