| University of Cambridge - 1884
...exterior angle made by producing one of the sides through the vertex. 9. Equal parallelograms, which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional. WEDNESDAY, December 5, 1883. 12$... | |
| GEORGE BRUCE HALSTED - 1885
...equal.) therefore, by 491, GH = BH'. In the same way HF = H'F', THEOREM VII. 511. Two triangles having **one angle of the one equal to one angle of the other, and** the sides about these angles proportional, are similar. HYPOTHESIS. £ B = £ G, and AB : BC : : FG... | |
| George Bruce Halsted - 1886 - 366 sider
...equal.) therefore, by 491, GH = BH'. In the same way HF = H'F', THEOREM VII. 511. Two triangles having **one angle of the one equal to one angle of the other, and** the sides about these angles proportional, are similar. HYPOTHESIS. £ B = $. G, and AB : BC : : FG... | |
| Association for the Improvement of Geometrical Teaching - 1888
...GH. Therefore AB : CD : : EF : GH. IV. 14, Part ii. QED THEOR. 14. If two triangles or parallelograms **have one angle of the one equal to one angle of the other,** their areas have to one another the ratio compounded of the ratios of the including sides of the first... | |
| New Brunswick. Board of Education - 1889
...and those which are opposite to the equal angles are homologous sides. 6. Equal parallelograms which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional. N. В.- --Female candidates will... | |
| Euclid - 1890 - 400 sider
....-. a AC = a BF. (/3) is true. EUCLID Proposition 15. THEOREMS — (a) Triangles of equal area which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional : (/3) and conversely, if two triangles... | |
| Queensland. Department of Public Instruction - 1890
...segments of the base. What is the corresponding proposition for the external bisector ? 8. Triangles which **have one angle of the one equal to one angle of the other,** have to one another the ratio which is compounded of the ratios of the sides about the equal angles.... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 515 sider
...parallelograms as in VI. 23, ||gm AC : ||gm CF :: rect. BC, CD : rect. EC, CG. Ex. 717. — Triangles which **have one angle of the one equal to one angle of the other** are to one another in the ratio compounded of the ratios of the sides containing the equal angles.... | |
| Royal Military College, Sandhurst - 1890 - 132 sider
...the line joining two alternate vertices of a given length. 7. Prove that equal parallelograms, which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional. 8. In a right-angled triangle, show... | |
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