 | Euclides - 1853 - 176 sider
...making any angle with ab; and in a С take any point d, and take a С the same multiple of ad, that a Ь is of the part which is to be cut off from it : join, b С, and draw de parallel to it : then ae is the part required to be cut off. Because ed is parallel... | |
 | William Somerville Orr - 1854 - 534 sider
...CD. PROPOSITION IX.— PROBLEM. From a given straight line (AB) to cut off any part required. From A draw a straight line AC, making any angle with AB ; and in it take any point D ; and take AC, the same multiple of AD, that AB is of the part to be cut off. Draw... | |
 | Euclides - 1855 - 230 sider
...PBOBLEM. From a given finite straight line (AB) to cut off any required part, or submultiple. _ SOLUTION. From the point A draw a straight line AC, making any...draw DE parallel to it : then AE is the part required tobecut of. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle ABC ; as... | |
 | John Playfair - 1855 - 334 sider
...; it is required to cut ofT from AB, a part which shall be contained in it a given number of times. From the point A draw a straight line AC making any angle with AB ; and in AC take any point 1), and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be... | |
 | Eucleides - 1860 - 396 sider
...PEOBLEM. From a given finite straight line (AB) to cut off any required part, or submultiple. SOLUTION. From the point A draw a straight line AC, making any...to it .then AE is the part required to be cut off. VI. 2. 6) V. 18. v. D. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle... | |
 | Robert Potts - 1860 - 380 sider
...off any part required. Let AB be the given straight line. It is required to cut off any part from it. From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclides - 1863 - 122 sider
...DBA. BC is to BA as BA is to BD; and in the triangles ABC and ACD, BC is to CA as CA is to CD (VI. 4). From the point A draw a straight line AC, making any angle BAC with AB. In AC take any point D, and make AC the same multiple of AD that AB is of the part to... | |
 | Euclides - 1864 - 448 sider
...off any part required. Let AB be the given straight line. It is required to cut off any part from it. From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclides - 1865 - 402 sider
...vi. 2.) Let AB be the given straight line. It is required to cut off any part from it. CONSTRUCTION From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. (i. 31.) Then AB shall be the part required to he out off. DEMONSTRATION Because ED is parallel... | |
 | Robert Potts - 1865 - 528 sider
...part required. Let AB be the given straight line. It is required to cut off any part from it. Prom the point A draw a straight line AC, making any angle...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
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From the point A draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required... 
