| University of Glasgow - 1883
...the side opposite are given. When is the problem impossible. 3. Show how to divide a straight line **into two parts so that the rectangle contained by the whole and** one of the parts may be equal to the square on the other part. If the length of the larger segment... | |
| Woolwich roy. military acad - 1884
...the squares on the two parts, together with twice the rectangle contained by the two parts. How must **a straight line be divided into two parts, so that the rectangle contained by** them may be the greatest possible ? 6. Draw a straight line from a given point, either without or in... | |
| 1884
...bisected at right angles by the straight line joining their centres. 3. Divide a given straight line **into two parts so that the rectangle contained by the whole and** one of the parts shall be equal to the square of the other part. 4. The angles in the same segment... | |
| Stewart W. and co - 1884
...therefore the squares of AD, DB are twice the squares of AC, CD. XI. — To divide a given straight line **into two parts, so that the rectangle contained by the whole and** one of the parts shall be equal to the square of the other part. It is required to divide AB into two... | |
| University of Cambridge - 1884
...each of the parte are together equal to the square on the whole line. 5. Divide a given straight line **into two parts, so that the rectangle contained by the whole and** one of the parts may be equal to the square on the other part. Prove that the rectangle contained by... | |
| F. B. Stevens - 1884 - 175 sider
...towards the same parts, are also themselves equal and parallel. 2. To divide a given straight line **into two parts, so that the rectangle contained by the whole and** one of the parts may be equal to the square on the other part. (LEGENDRE.) 1. In an isosceles triangle... | |
| Euclid, John Casey - 1885 - 312 sider
...together with four times the square on the line joining the points of bisection. 6. Divide a given line **into two parts, so that the rectangle contained by the whole and** one segment may be equal to any multiple of the square on the other segment. 7. If P be any point in... | |
| 1885
...parallelogram are equal to one another, and that the diagonal bisects it. 6. Divide a straight line **into two parts, so that the rectangle contained by the whole and** one of the parts shall be equal to the square of the other part. Female Candidates for Class I. will... | |
| GEORGE BRUCE HALSTED - 1885
...rectangle BA,AF + AG2 = GF* = GH2 = AH2 + A(?, by 243 ; 112 PROBLEM II. 313. To divide a given sect **into two parts so that the rectangle contained by the whole and** one of the parts shall be equal to the square on the other part. Jf X GIVEN, the sect AB. REQUIRED,... | |
| Euclides - 1885
...together with lour times the square on the line joining the points of bisection. 6. Divide a given line **into two parts, so that the rectangle contained by the whole and** one segment may be equal to any multiple of the square on the other segment. 7. If P be any point in... | |
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