Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Elements of Algebra - Side 1151838 - 355 siderUten tilgangsbegrensning - Om denne boken
| Lyman Cobb - 1832 - 228 sider
...wiite the cube of this quotient figure, and call the amount the subtrahend. 7. Substract the subtrahend from the dividend, and to the remainder bring down the next period for anew dividrnd, with wiiieh proceed HS before; anci so on, till the whole is finished. NOTE. — If... | |
| Nicolas Pike - 1832 - 544 sider
...the cube of the last quotient figure, and call their sum the subtrahend. 5. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for anew dividend, with whieh proceed as before, and so on until the whole be finished. EXAMPLE. Required... | |
| Samuel Read Hall - 1832 - 294 sider
...the last quotient, and cube the last quotient, and add these products together and take the amount from the dividend. and to the remainder bring down the next period. Proceed as before, till the whole is finished. 1. What is the cube root of 15625? 15625(25 root The... | |
| Daniel Adams - 1833 - 268 sider
...the cube of this quotient figure, and call their amount the subtrahend. VII. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on, till the whole is finished. Note 1. If it happens that the... | |
| Catharine Esther Beecher - 1833 - 296 sider
...and add these three results together for a subtrahend. 5. Subtract the subtrahend from the dividend. To the remainder bring down the next period, for a new dividend, and proceed as before. If it happens in any case, that the divisor is not contained in the dividend,... | |
| William Templeton (engineer.) - 1833 - 224 sider
...in the root ; add these three last found numbers together, and subtract this sum from the dividend ; to the remainder bring down the next period for a new dividend, and proceed as before. EXAMPLE. — Required the cube root of 44419494". 444194947(763 343 7 x 7 x... | |
| Frederick Emerson - 1834 - 300 sider
...also at the right hand of the divisor. Multiply the divisor, thus increased, by the last figure in the root, and subtract the product from the dividend,...remainder bring down the next period for a new dividend. . Fourthly — Double the root already found for a new divisor, and continue to operate as before,... | |
| Frederick Emerson - 1835 - 300 sider
...divisor completed. Lastly — Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down tht next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that,... | |
| James L. Connolly (mathematician.) - 1835 - 264 sider
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
| Benjamin Snowden - 1835 - 108 sider
...greater than the dividend, put a less figure than the last to the root, and alter the work. 8. — To the remainder bring down the next period for a new dividend, with which proceed as with the first dividend, until all the periods are brought down. Prove the work... | |
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