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" From half the sum of the three sides, subtract each side severally; multiply the half sum, and the three remainders together, and the square root of the product will be the area required. "
Principles of Architecture: Comprising Fundamental Rules of the Art, with ... - Side 92
av Peter Nicholson, Joseph Gwilt - 1848 - 280 sider
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A System of Geometry and Trigonometry: With a Treatise on Surveying ... in ...

Abel Flint - 1830 - 284 sider
...From half the sum of the sides subtract each side separately. Multiply the half sum and the several remainders together, and the square root of the product will be the area. — ED . her corresponding to one half the sum of those logarithms will be the area of the triangle....
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A Key to the Western Calculator: Containing the Solution of All the Examples ...

John Armstrong - 1831 - 139 sider
...three sides subtract each side severally. 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. RULE. ii. Any two sides of a triangle being multiplied together, and the product again by half the...
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A New and Easy Introduction to the Mathematics: Containing. A system of ...

Ira Wanzer - 1831 - 396 sider
...subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root of the product will be the area of the triangle. Ex. 1. What is the area of a triangle whose base is 15 feet, and perpendicular height...
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A system of practical arithmetic

Samuel Young (of Manchester.) - 1833
...many acres does it contain ? When the three sides only are given. RULE 2. From half the sum of the sides subtract each side severally : multiply the half sum and the three Remainders continually together, and the square root of their Product will be the area. (3) How many acres are...
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The Tutor's Assistant: Being a Compendium of Practical Arithmetic, for the ...

Francis Walkingame - 1833
...base, 9 feet 4 inches ? ADB RULE 2. When the three sides only are given. — From half the sum of the sides subtract each side severally: multiply the half sum and the three remainders continually together ; and the square root of their product will be the area. (3) The three sides of...
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A treatise on practical geometry, mensuration, conic sections, gauging, and ...

Ireland commissioners of nat. educ - 1834
...to find its orea. RULE I. From, half the sum of the three sides subtract each side separately, then multiply the half sum and the three remainders together, and the square root of the last product will be the area of the triangle.* height gives the area of a rectangular parallelogram,...
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The American Student's Guide: Containing a Compendious System of Theoretical ...

George Alfred - 1834 - 312 sider
...sides subtract each side several! y, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. AN EXAMPLE. In the triangle ABC let the side AC be 40 poles, CB50, and AB 60 ; required, the area in...
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An Introduction to Mensuration and Practical Geometry

John Bonnycastle - 1835 - 288 sider
...the sum of the four sides subtract each side severally; then multiply the four remainders continually together, and the square root of the product will be the area. 2. Required the area of a trapezium whose diagonal is 80.5, and the two perpendiculars 24.5 and 30.1....
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The Elements of Algebra: Designed for the Use of Students in the University

John Hind - 1837 - 539 sider
...- \/s (s — «)(« — b) (s — c) From half the sum of the sides, subtract each side separately: multiply the half sum and the three remainders together,...and the square root of the product will be the area. Ex. 4. Required the area of a triangle whose sides are \2a* +262-c2, \A a2 + 2 c2 - b", and By the...
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A Treatise on Mensuration for the Use of Schools

1837 - 262 sider
...to find its area. RULE I. From half the sum of the three sides subtract each side separately, then multiply the half sum and the three remainders together, and the square root of the last product will be the area of the triangle.* RULE II. Divide the difference between the squares...
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