| Abel Flint - 1830 - 284 sider
...From half the sum of the sides subtract each side separately. Multiply the half sum and the several **remainders together, and the square root of the product will be the area.** — ED . her corresponding to one half the sum of those logarithms will be the area of the triangle.... | |
| John Armstrong - 1831 - 139 sider
...three sides subtract each side severally. 2. Multiply the half sum and the three remainders continually **together, and the square root of the product will be the area required.** RULE. ii. Any two sides of a triangle being multiplied together, and the product again by half the... | |
| Ira Wanzer - 1831 - 396 sider
...subtract each side separately ; then multiply the said half sum and the three remainders continually **together, and the square root of the product will be the area** of the triangle. Ex. 1. What is the area of a triangle whose base is 15 feet, and perpendicular height... | |
| Samuel Young (of Manchester.) - 1833
...many acres does it contain ? When the three sides only are given. RULE 2. From half the sum of the **sides subtract each side severally : multiply the half sum and the three Remainders** continually together, and the square root of their Product will be the area. (3) How many acres are... | |
| Francis Walkingame - 1833
...base, 9 feet 4 inches ? ADB RULE 2. When the three sides only are given. — From half the sum of the **sides subtract each side severally: multiply the half sum and the three remainders** continually together ; and the square root of their product will be the area. (3) The three sides of... | |
| Ireland commissioners of nat. educ - 1834
...to find its orea. RULE I. From, half the sum of the three sides subtract each side separately, then **multiply the half sum and the three remainders together, and the square root of the** last product will be the area of the triangle.* height gives the area of a rectangular parallelogram,... | |
| George Alfred - 1834 - 312 sider
...sides subtract each side several! y, then multiply the half sum and the three remainders continually **together, and the square root of the product will be the area required.** AN EXAMPLE. In the triangle ABC let the side AC be 40 poles, CB50, and AB 60 ; required, the area in... | |
| John Bonnycastle - 1835 - 288 sider
...the sum of the four sides subtract each side severally; then multiply the four remainders continually **together, and the square root of the product will be the area.** 2. Required the area of a trapezium whose diagonal is 80.5, and the two perpendiculars 24.5 and 30.1.... | |
| John Hind - 1837 - 539 sider
...- \/s (s — «)(« — b) (s — c) From half the sum of the sides, subtract each side separately: **multiply the half sum and the three remainders together,...and the square root of the product will be the area.** Ex. 4. Required the area of a triangle whose sides are \2a* +262-c2, \A a2 + 2 c2 - b", and By the... | |
| 1837 - 262 sider
...to find its area. RULE I. From half the sum of the three sides subtract each side separately, then **multiply the half sum and the three remainders together, and the square root of the** last product will be the area of the triangle.* RULE II. Divide the difference between the squares... | |
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