| Frederick Augustus Griffiths - 1839
...product will be the area. To find the area of a triangle whose three sides are given.—From half the **sum of the three sides, subtract each side severally;...square root of the product will be the area required.** Two sides of a right angled triangle being given to find the third side.—When the two sides forming... | |
| Frederick Augustus Griffiths - 1840
...Square yards. Area required. To find the Area of a Triangle, whose three Sides are given. From half the **sum of the three sides, subtract each side severally...of the product will be the Area required. Example.** — Required the Area of a Triangle, whose sides are 50, 40, and 30 feet. 50 + 40 + 30.. fin half sum... | |
| Abraham Crocker - 1841
...the area. RULE II. When the three sides are given. Add the sides together. From half the sum of the **sides subtract each side severally. Multiply the half sum and the three remainders together, and the** square-root of the last product will be the area. That is, •/a + b + c^ — a + b + c a— b + ca... | |
| John M'Nevin - 1841 - 280 sider
...sum, subtract each side severally; from the half sum multiply the half sum and the three differences **together, and the square root of the product will be the area.** 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans.... | |
| John M'Nevin - 1841 - 280 sider
...sum, subtract each side severally; from the half sum multiply the half sum and the three differences **together, and the square root of the product will be the area.** 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans.... | |
| 1845
...area. When only the three sides of a triangle can be given, to find the area. Rule. — From half the **sum of the three sides, subtract each side severally...remainders together, and the square root of the product** is equal the area required. Required the area of a triangle, whose three sides are respectively 50,... | |
| William Watson (of Beverley.) - 1845
...crooked fence, so as to include as much on one side as they exclude on the other. remainders continually **together, and the square root of the product will be the area.** EXAMPLES. I . Required the area of a triangle, the sides of which are 26, 28, and 30. 26 28 42 42 42... | |
| 1847 - 178 sider
...XT7S I When only the three sides of a triangle can be given, to find the artaRule — Prom half the **sum of the three sides subtract each side severally...remainders together, and the square root of the product** is equal the area requiredRequired the area of a triangle, whose three sides are respectively 50, 40,... | |
| Anthony Nesbit - 1847 - 426 sider
...method. 4. When the three sides of a triangle are given, the area may be found as follows. From half the **sum of the three sides subtract each side severally ; multiply the half sum and the three remainders** continually together, and the square root of the last product will be the area required. This method... | |
| William Vogdes - 1847 - 256 sider
...does it contain ? PROBLEM XI. Given three sides of a triangle, to find the area. RULE. From half the **sum of the three sides subtract each side severally. Multiply the half sum and the three remainders** continually together, and the square root of the product will be the area required. EXAMPLES 1. What... | |
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